C#实现程序开机启动

如何用c#实现开机启动?其实用c#实现程序的开机启动大致有两种方法，，就是写入注册表或者采用服务程序，最近一直研究着用C#来操作注册表，下面介绍的方法便是用注册表来实现程序随开机启动(高手就不用看了,嘿嘿...)。
1)引入命名空间 using Microsoft.Win32;

//打开注册表子项
RegistryKey key = Registry.LocalMachine.OpenSubKe("SOFTWARE//Microsoft//Windows//CurrentVersion//Run",true);

key.SetValue(程序的名称, 程序的路径);//设置为开机启动
为了安全性，还应该判断设置的文件是否存在以及该子项是否存在，所有完整代码如下：

private void btnShowOpen_Click(object sender, EventArgs e)
        {
            OpenFileDialog open = new OpenFileDialog();
            open.Filter = "可执行文件(*.exe)|*.exe";
            if (open.ShowDialog() == DialogResult.OK)
            {
                txtPath.Text = open.FileName;
            }
        }

        private bool runWhenStart(bool started,string exeName, string path)
        {          
            RegistryKey key = Registry.LocalMachine.OpenSubKey("SOFTWARE//Microsoft//Windows//CurrentVersion//Run", true);//打开注册表子项
            if (key == null)//如果该项不存在的话，则创建该子项
            {
                key = Registry.LocalMachine.CreateSubKey("SOFTWARE//Microsoft//Windows//CurrentVersion//Run");
            }
            if (started == true)
            {
                try
                {                   
                    key.SetValue(exeName, path);//设置为开机启动
                    key.Close();
                }
                catch
                {
                    return false;
                }
            }
            else
            {
                try
                {                   
                    key.DeleteValue(exeName);//取消开机启动
                    key.Close();
                }
                catch
                {
                    return false;
                }
            }
            return true;
        }