如何调用docker swarm service的API来创建及更新服务

时间:2024-03-30 13:19:02

平衡的推进,先作一个原型吧。

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import requests
import json

#定义docker swarm的管理节点ip,端口号,API版本,服务名, 服务URL
#在后期集成到自动化部署时,需要精简数据结构,完善data, 增加精准判断及空间回收
#API更多用途参考: https://docs.docker.com/engine/api/v1.29/
docker_swarm_ip_port = "ip:port"
docker_swarm_api_version = "v1.29"
docker_swarm_service_name = "tomcatbv"

get_service_url = "http://%s/%s/services/%s" %(docker_swarm_ip_port, docker_swarm_api_version, docker_swarm_service_name)

data = {
  "Name": "tomcatbv",
  "TaskTemplate": {
    "ContainerSpec": {
      "Image": "harbor_op/project_name/tomcat:20170620demo",
    },
    "Placement": {},
    "RestartPolicy": {
      "Condition": "on-failure",
      "Delay": 10000000000,
      "MaxAttempts": 10
    }
  },
  "Mode": {
    "Replicated": {
      "Replicas": 1
    }
  },
  "UpdateConfig": {
    "Parallelism": 2,
    "FailureAction": "pause",
  },
  "RollbackConfig": {
    "Parallelism": 1,
  },
  "Labels": {
    "foo": "bar"
  }
}


#创建docker swarm service服务
def create_service():
    url = "http://%s/%s/services/create" %(docker_swarm_ip_port, docker_swarm_api_version)
    data_json = json.dumps(data)
    r = requests.post(url, data=data_json)
    print r.text
    if r.status_code == 201:
        print "created ok"
    else:
        print "create error"
        sys.exit()

#更新docker swarm service服务
def update_service(version_index):
    url = "http://%s/%s/services/%s/update?version=%s" %(docker_swarm_ip_port, docker_swarm_api_version, docker_swarm_service_name, version_index)
    data_json = json.dumps(data)
    r = requests.post(url, data=data_json)
    print version_index, r.text, r.status_code
    if r.status_code == 200:
        print "updated ok"
    else:
        print "update error"
        sys.exit()

def main():
    get_service_url = "http://%s/%s/services/%s" %(docker_swarm_ip_port, docker_swarm_api_version, docker_swarm_service_name)
    r = requests.get(get_service_url)
    print get_service_url, r.status_code, r.text
    if r.status_code != 200:
        create_service()
    else:
        version_index = eval(r.text)["Version"]["Index"]
        update_service(version_index)
    

if __name__ == "__main__":
    main()

如何调用docker swarm service的API来创建及更新服务