将字符串拆分为基于分隔符的字符串数组。

I'm trying to find a Delphi function that will split an input string into an array of strings based on a delimiter. I've found a lot on Google, but all seem to have their own issues and I haven't been able to get any of them to work.

我正在尝试找到一个Delphi函数，它将一个输入字符串分割为一个基于分隔符的字符串数组。我在谷歌上发现了很多，但似乎都有他们自己的问题，我还没能让他们工作。

I just need to split a string like: "word:doc,txt,docx" into an array based on ':'. The result would be ['word', 'doc,txt,docx'].

我只需要将一个字符串像:“word:doc,txt,docx”拆分为一个基于“:”的数组。结果将是['word'， 'doc,txt,docx']。

Does anyone have a function that they know works?

有没有人有自己知道的功能?

Thank you

谢谢你！

15 个解决方案

#1

you can use the TStrings.DelimitedText property for split an string

你可以使用TStrings。分隔字符串的分隔文本属性。

check this sample

检查这个样品

program Project28;

{$APPTYPE CONSOLE}

uses
  Classes,
  SysUtils;

procedure Split(Delimiter: Char; Str: string; ListOfStrings: TStrings) ;
begin
   ListOfStrings.Clear;
   ListOfStrings.Delimiter       := Delimiter;
   ListOfStrings.StrictDelimiter := True; // Requires D2006 or newer.
   ListOfStrings.DelimitedText   := Str;
end;


var
   OutPutList: TStringList;
begin
   OutPutList := TStringList.Create;
   try
     Split(':', 'word:doc,txt,docx', OutPutList) ;
     Writeln(OutPutList.Text);
     Readln;
   finally
     OutPutList.Free;
   end;
end.

UPDATE

更新

See this link for an explanation of StrictDelimiter.

请参阅此链接，以解释StrictDelimiter。

#2

There is no need for engineering a Split function. It already exists, see: Classes.ExtractStrings.

没有必要设计一个分割函数。它已经存在，见:类。

Use it in a following manner:

以下列方式使用:

program Project1;

{$APPTYPE CONSOLE}

uses
  Classes;

var
  List: TStrings;
begin
  List := TStringList.Create;
  try
    ExtractStrings([':'], [], PChar('word:doc,txt,docx'), List);
    WriteLn(List.Text);
    ReadLn;
  finally
    List.Free;
  end;
end.

And to answer the question fully; List represents the desired array with the elements:

并充分回答这个问题;列表表示所需的数组元素:

List[0] = 'word'
List[1] = 'doc,txt,docx'

#3

StrUtils.SplitString in Delphi 2010

StrUtils。SplitString在Delphi 2010

#4

Using the SysUtils.TStringHelper.Split function, introduced in Delphi XE3:

使用SysUtils.TStringHelper。分离函数，引入Delphi XE3:

var
  MyString: String;
  Splitted: TArray<String>;
begin
  MyString := 'word:doc,txt,docx';
  Splitted := MyString.Split([':']);
end.

This will split a string with a given delimiter into an array of strings.

这将把一个字符串与一个给定的分隔符拆分为字符串数组。

#5

Similar to the Explode() function offered by Mef, but with a couple of differences (one of which I consider a bug fix):

与Mef提供的爆炸()功能类似，但有一些区别(其中一个我认为是bug修复):

  type
    TArrayOfString = array of String;


  function SplitString(const aSeparator, aString: String; aMax: Integer = 0): TArrayOfString;
  var
    i, strt, cnt: Integer;
    sepLen: Integer;

    procedure AddString(aEnd: Integer = -1);
    var
      endPos: Integer;
    begin
      if (aEnd = -1) then
        endPos := i
      else
        endPos := aEnd + 1;

      if (strt < endPos) then
        result[cnt] := Copy(aString, strt, endPos - strt)
      else
        result[cnt] := '';

      Inc(cnt);
    end;

  begin
    if (aString = '') or (aMax < 0) then
    begin
      SetLength(result, 0);
      EXIT;
    end;

    if (aSeparator = '') then
    begin
      SetLength(result, 1);
      result[0] := aString;
      EXIT;
    end;

    sepLen := Length(aSeparator);
    SetLength(result, (Length(aString) div sepLen) + 1);

    i     := 1;
    strt  := i;
    cnt   := 0;
    while (i <= (Length(aString)- sepLen + 1)) do
    begin
      if (aString[i] = aSeparator[1]) then
        if (Copy(aString, i, sepLen) = aSeparator) then
        begin
          AddString;

          if (cnt = aMax) then
          begin
            SetLength(result, cnt);
            EXIT;
          end;

          Inc(i, sepLen - 1);
          strt := i + 1;
        end;

      Inc(i);
    end;

    AddString(Length(aString));

    SetLength(result, cnt);
  end;

Differences:

差异:

aMax parameter limits the number of strings to be returned
aMax参数限制返回的字符串的数量。
If the input string is terminated by a separator then a nominal "empty" final string is deemed to exist
如果输入字符串被分隔符终止，那么将认为存在一个名义上的“空”最终字符串。

Examples:

例子:

SplitString(':', 'abc') returns      :    result[0]  = abc

SplitString(':', 'a:b:c:') returns   :    result[0]  = a
                                          result[1]  = b
                                          result[2]  = c
                                          result[3]  = <empty string>

SplitString(':', 'a:b:c:', 2) returns:    result[0]  = a
                                          result[1]  = b

It is the trailing separator and notional "empty final element" that I consider the bug fix.

我认为bug修复是尾随分隔符和抽象的“空的最终元素”。

I also incorporated the memory allocation change I suggested, with refinement (I mistakenly suggested the input string might at most contain 50% separators, but it could conceivably of course consist of 100% separator strings, yielding an array of empty elements!)

我还结合了我建议的内存分配更改(我错误地建议输入字符串最多可以包含50%的分隔符，但是可以想象的是，它当然包含100%的分隔符字符串，产生大量的空元素!)

#6

I always use something similar to this:

我总是用类似的东西:

Uses
   StrUtils, Classes;

Var
  Str, Delimiter : String;
begin
  // Str is the input string, Delimiter is the delimiter
  With TStringList.Create Do
  try
    Text := ReplaceText(S,Delim,#13#10);

    // From here on and until "finally", your desired result strings are
    // in strings[0].. strings[Count-1)

  finally
    Free; //Clean everything up, and liberate your memory ;-)
  end;

end;

#7

Explode is very high speed function, source alhoritm get from TStrings component. I use next test for explode: Explode 134217733 bytes of data, i get 19173962 elements, time of work: 2984 ms.

爆炸是非常高速的函数，源alhoritm从TStrings中得到。我使用下一个爆炸测试:爆炸134217733字节的数据，我得到19173962个元素，工作时间:2984毫秒。

Implode is very low speed function, but i write it easy.

内爆是非常低速的函数，但我写得很简单。

{ ****************************************************************************** }
{  Explode/Implode (String <> String array)                                      }
{ ****************************************************************************** }
function Explode(S: String; Delimiter: Char): Strings; overload;
var I, C: Integer; P, P1: PChar;
begin
    SetLength(Result, 0);
    if Length(S) = 0 then Exit;
    P:=PChar(S+Delimiter); C:=0;
    while P^ <> #0 do begin
       P1:=P;
       while (P^ <> Delimiter) do P:=CharNext(P);
       Inc(C);
       while P^ in [#1..' '] do P:=CharNext(P);
       if P^ = Delimiter then begin
          repeat
           P:=CharNext(P);
          until not (P^ in [#1..' ']);
       end;
    end;
    SetLength(Result, C);
    P:=PChar(S+Delimiter); I:=-1;
    while P^ <> #0 do begin
       P1:=P;
       while (P^ <> Delimiter) do P:=CharNext(P);
       Inc(I); SetString(Result[I], P1, P-P1);
       while P^ in [#1..' '] do P:=CharNext(P);
       if P^ = Delimiter then begin
          repeat
           P:=CharNext(P);
          until not (P^ in [#1..' ']);
       end;
    end;
end;

function Explode(S: String; Delimiter: Char; Index: Integer): String; overload;
var I: Integer; P, P1: PChar;
begin
    if Length(S) = 0 then Exit;
    P:=PChar(S+Delimiter); I:=1;
    while P^ <> #0 do begin
       P1:=P;
       while (P^ <> Delimiter) do P:=CharNext(P);
        SetString(Result, P1, P-P1);
        if (I <> Index) then Inc(I) else begin
           SetString(Result, P1, P-P1); Exit;
        end;
       while P^ in [#1..' '] do P:=CharNext(P);
       if P^ = Delimiter then begin
          repeat
           P:=CharNext(P);
          until not (P^ in [#1..' ']);
       end;
    end;
end;

function Implode(S: Strings; Delimiter: Char): String;
var iCount: Integer;
begin
     Result:='';
     if (Length(S) = 0) then Exit;
     for iCount:=0 to Length(S)-1 do
     Result:=Result+S[iCount]+Delimiter;
     System.Delete(Result, Length(Result), 1);
end;

#8

var  
    su  : string;        // What we want split
    si  : TStringList;   // Result of splitting
    Delimiter : string;
    ...
    Delimiter := ';';
    si.Text := ReplaceStr(su, Delimiter, #13#10);

Lines in si list will contain splitted strings.

si列表中的行将包含分裂的字符串。

#9

Here is an implementation of an explode function which is available in many other programming languages as a standard function:

这里是一个爆炸函数的实现，它在许多其他编程语言中作为一个标准函数可用:

type 
  TStringDynArray = array of String;

function Explode(const Separator, S: string; Limit: Integer = 0): TStringDynArray; 
var 
  SepLen: Integer; 
  F, P: PChar; 
  ALen, Index: Integer; 
begin 
  SetLength(Result, 0); 
  if (S = '') or (Limit < 0) then Exit; 
  if Separator = '' then 
  begin 
    SetLength(Result, 1); 
    Result[0] := S; 
    Exit; 
  end; 
  SepLen := Length(Separator); 
  ALen := Limit; 
  SetLength(Result, ALen); 

  Index := 0; 
  P := PChar(S); 
  while P^ <> #0 do 
  begin 
    F := P; 
    P := AnsiStrPos(P, PChar(Separator)); 
    if (P = nil) or ((Limit > 0) and (Index = Limit - 1)) then P := StrEnd(F); 
    if Index >= ALen then 
    begin 
      Inc(ALen, 5); 
      SetLength(Result, ALen); 
    end; 
    SetString(Result[Index], F, P - F); 
    Inc(Index); 
    if P^ <> #0 then Inc(P, SepLen); 
  end; 
  if Index < ALen then SetLength(Result, Index); 
end;

Sample usage:

示例用法:

var
  res: TStringDynArray;
begin
  res := Explode(':', yourString);

#10

You can make your own function which returns TArray of string:

您可以创建自己的函数，它返回字符串的TArray:

function mySplit(input: string): TArray<string>;
var
  delimiterSet: array [0 .. 0] of char; 
     // split works with char array, not a single char
begin
  delimiterSet[0] := '&'; // some character
  result := input.Split(delimiterSet);
end;

#11

I wrote this function which returns linked list of separated strings by specific delimiter. Pure free pascal without modules.

我编写了这个函数，它通过特定的分隔符返回分离字符串的链表。没有模块的纯*pascal。

Program split_f;

type
    PTItem = ^TItem;
    TItem = record
        str : string;
        next : PTItem;
    end;

var
    s : string;
    strs : PTItem;

procedure split(str : string;delim : char;var list : PTItem);
var
    i : integer;
    buff : PTItem;
begin
    new(list);
    buff:= list;
    buff^.str:='';
    buff^.next:=nil;

    for i:=1 to length(str) do begin
        if (str[i] = delim) then begin
            new(buff^.next);
            buff:=buff^.next;
            buff^.str := '';
            buff^.next := nil;
        end
        else
        buff^.str:= buff^.str+str[i];
    end;
end;

procedure print(var list:PTItem);
var
    buff : PTItem;
begin
    buff := list;
    while buff<>nil do begin
        writeln(buff^.str);
        buff:= buff^.next;
    end;
end;

begin

    s := 'Hi;how;are;you?';

    split(s, ';', strs);
    print(strs);


end.

#12

Jedi Code Library provides an enhanced StringList with built-in Split function, that is capable of both adding and replacing the existing text. It also provides reference-counted interface. So this can be used even with older Delphi versions that have no SplitStrings and without careful and a bit tedious customizations of stock TStringList to only use specified delimiters.

Jedi代码库提供了一个增强的StringList，具有内置的Split函数，它可以添加和替换现有的文本。它还提供了引用计数接口。因此，即使有更老的Delphi版本也可以使用它，这些版本没有splitstring，而且不需要仔细地进行一些繁琐的定制，只使用指定的分隔符。

For example given text file of lines like Dog 5 4 7 one can parse them using:

例如，给定的文本文件，比如狗5 4 7，可以使用:

var slF, slR: IJclStringList; ai: TList<integer>; s: string; i: integer;
    action: procedure(const Name: string; Const Data: array of integer);

slF := TJclStringList.Create; slF.LoadFromFile('some.txt');
slR := TJclStringList.Create;
for s in slF do begin
    slR.Split(s, ' ', true);
    ai := TList<Integer>.Create;
    try
       for i := 1 to slR.Count - 1 do
           ai.Add(StrToInt(slR[i]));
       action(slR[0], ai.ToArray);
    finally ai.Free; end;
end;

http://wiki.delphi-jedi.org/wiki/JCL_Help:IJclStringList.Split@string@string@Boolean

http://wiki.delphi-jedi.org/wiki/JCL_Help IJclStringList.Split@string@string@Boolean

#13

This will solve your problem

这会解决你的问题。

interface
   TArrayStr = Array Of string;

implementation

function SplitString(Text: String): TArrayStr;
var
   intIdx: Integer;
   intIdxOutput: Integer;
const
   Delimiter = ';';
begin
   intIdxOutput := 0;
   SetLength(Result, 1);
   Result[0] := ''; 

   for intIdx := 1 to Length(Text) do
   begin
      if Text[intIdx] = Delimiter then
      begin
         intIdxOutput := intIdxOutput + 1;
         SetLength(Result, Length(Result) + 1);
      end
      else
         Result[intIdxOutput] := Result[intIdxOutput] + Text[intIdx];
   end;
end;

#14

//Basic functionality of a TStringList solves this:


uses Classes  //TStringList 
    ,types    //TStringDynArray
    ,SysUtils //StringReplace()
    ;

....

 //--------------------------------------------------------------------------
 function _SplitString(const s:string; const delimiter:Char):TStringDynArray;
  var sl:TStringList;
      i:integer;
  begin
  sl:=TStringList.Create;

  //separete delimited items by sLineBreak;TStringlist will do the job:
  sl.Text:=StringReplace(s,delimiter,sLineBreak,[rfReplaceAll]);

  //return the splitted string as an array:
  setlength(Result,sl.count);
  for i:=0 to sl.Count-1
   do Result[i]:=sl[i];

  sl.Free;
  end;



//To split a FileName (last item will be the pure filename itselfs):

 function _SplitPath(const fn:TFileName):TStringDynArray;
  begin
  result:=_SplitString(fn,'\');
  end;

#15

The base of NGLG answer https://*.com/a/8811242/6619626 you can use the following function:

NGLG的基础是https://*.com/a/8811242/6619626，你可以使用以下功能:

type
OurArrayStr=array of string;

function SplitString(DelimeterChars:char;Str:string):OurArrayStr;
var
seg: TStringList;
i:integer;
ret:OurArrayStr;
begin
    seg := TStringList.Create;
    ExtractStrings([DelimeterChars],[], PChar(Str), seg);
    for i:=0 to seg.Count-1 do
    begin
         SetLength(ret,length(ret)+1);
         ret[length(ret)-1]:=seg.Strings[i];
    end;
    SplitString:=ret;
    seg.Free;
end;

It works in all Delphi versions.

它适用于所有德尔福版本。

#1