I have a string/pattern like this:
我有一个像这样的字符串/模式：
[xy][abc]
I try to get the values contained inside the square brackets:
我尝试获取方括号内包含的值：
- xy
- XY
- abc
- ABC
There are never brackets inside brackets. Invalid: [[abc][def]]
括号内没有括号。无效：[[abc] [def]]
So far I've got this:
到目前为止，我有这个：
import re
pattern = "[xy][abc]"
x = re.compile("\[(.*?)\]")
m = outer.search(pattern)
inner_value = m.group(1)
print inner_value
But this gives me only the inner value of the first square brackets.
但这只给了我第一个方括号的内在价值。
Any ideas? I don't want to use string split functions, I'm sure it's possible somehow with RegEx alone.
有任何想法吗？我不想使用字符串拆分函数，我确信单独使用RegEx可能会以某种方式。
3 个解决方案
#1
17
re.findall is your friend here:
re.findall是你的朋友：
>>> import re
>>> sample = "[xy][abc]"
>>> re.findall(r'\[([^]]*)\]',sample)
['xy', 'abc']
#2
4
>>> import re
>>> re.findall("\[(.*?)\]", "[xy][abc]")
['xy', 'abc']
#3
3
I suspect you're looking for re.findall.
我怀疑你正在寻找re.findall。
See this demo:
看这个演示：
import re
my_regex = re.compile(r'\[([^][]+)\]')
print(my_regex.findall('[xy][abc]'))
['xy', 'abc']
If you want to iterate over matches instead of match strings, you might look at re.finditer instead. For more details, see the Python re docs.
如果你想迭代匹配而不是匹配字符串，你可能会改为查看re.finditer。有关更多详细信息，请参阅Python re docs。
#1
17
re.findall is your friend here:
re.findall是你的朋友：
>>> import re
>>> sample = "[xy][abc]"
>>> re.findall(r'\[([^]]*)\]',sample)
['xy', 'abc']
#2
4
>>> import re
>>> re.findall("\[(.*?)\]", "[xy][abc]")
['xy', 'abc']
#3
3
I suspect you're looking for re.findall.
我怀疑你正在寻找re.findall。
See this demo:
看这个演示：
import re
my_regex = re.compile(r'\[([^][]+)\]')
print(my_regex.findall('[xy][abc]'))
['xy', 'abc']
If you want to iterate over matches instead of match strings, you might look at re.finditer instead. For more details, see the Python re docs.
如果你想迭代匹配而不是匹配字符串，你可能会改为查看re.finditer。有关更多详细信息，请参阅Python re docs。