逆波兰表达式(RPN)算法简单实现

时间:2023-10-12 19:23:08

一、预处理

给定任意四则运算的字符串表达式(中缀表达式),preDeal预先转化为对应的字符串数组,其目的在于将操作数和运算符分离。

例如给定四则运算内的中缀表达式:

String infix = "100+8*5-(10/2)*5+10.5";

字符串数组化后得:

{"100","+","8","*","5","-","(","10","/","2",")","+","10.5"}

二、中缀表达式转后缀表达式

规则:

遍历中缀表达式,

A、如果遇到操作数直接输出

B、如果遇到运算符,分情况:

B1:如果是*、/或者(这三个运算符,直接压栈

B2:如果是),则出栈直到遇到(位置。(左括号和有括号并不参与拼接后缀表达式)。

B3:如果是+或者-,先弹栈直到栈空,再讲当前的+或者-压栈。

其中情况B可以总结:

遇到右括号出栈直到匹配左括号,遇到操作符,如果其优先级高于栈顶元素,则继续压栈,否则出栈。

三、计算后缀表达式

规则:

遍历后缀表达式:

A、遇到操作数压栈

B、遇到运算符则将栈顶和次栈顶两个元素取出参与对应的运算,再将运算结结果压栈。

四、Java算法实现

 package agstring;
import java.util.*; public class RPN {
public static String[] preDeal(String infix){
infix = infix.trim();
int length = infix.length();
ArrayList<String> infixOfArrayList = new ArrayList<String>();
char currChar;
int index = 0;
final String regex = "\\+|-|\\*|\\/|\\(|\\)";
for (int i = 0; i < length; i++) {
currChar = infix.charAt(i);
if(String.valueOf(currChar).matches(regex)){//运算符
if (index < i) {
infixOfArrayList.add(infix.substring(index,i));//add数字
}
infixOfArrayList.add(String.valueOf(currChar));
index = i+1;
}
}
infixOfArrayList.add(infix.substring(index,length));
return infixOfArrayList.toArray(new String[infixOfArrayList.size()]);
}
public static String[] getPostfix(String infix) {
String[] infixOfAry = preDeal(infix);
int length = infixOfAry.length;
ArrayDeque<String> stack = new ArrayDeque<String>();
String currString = "";
final String regex = "\\+|-|\\*|\\/|\\(|\\)";
ArrayList<String> postfixOfArrayList = new ArrayList<String>();
for (int i = 0; i < length; i++) {
currString = infixOfAry[i];
if (currString.matches(regex)) {//symbol
if (currString.matches("\\*|\\/|\\(")) {
stack.offerFirst(currString);
}else {//),+,-
String top = "";
if(currString.equals(")")){
while(!stack.isEmpty()){
top = stack.removeFirst();
if (top.equals("(")) {
break;
}
postfixOfArrayList.add(top);
}
}else {//+ ,-
if (!stack.isEmpty()) {
top = stack.peekFirst();
if (top.equals("*") || top.equals("/")) {
while(!stack.isEmpty()){
postfixOfArrayList.add(stack.removeFirst());
}
}
}
stack.offerFirst(currString);
}
}
}else {//number
postfixOfArrayList.add(currString);
}
}
while(!stack.isEmpty()){
postfixOfArrayList.add(stack.removeFirst());
}
return postfixOfArrayList.toArray(new String[postfixOfArrayList.size()]);
}
public static double computePostfix(String infix){
String[] postfixAry = getPostfix(infix);
ArrayDeque<Double> stack = new ArrayDeque<Double>();
int length = postfixAry.length;
String currString = "";
final String regex = "\\+|-|\\*|\\/|\\(|\\)";
double operandOne,operandTwo;
for (int i = 0; i < length; i++) {
currString = postfixAry[i];
if (currString.matches(regex)) {
operandOne = stack.removeFirst();
operandTwo = stack.removeFirst();
switch (currString.charAt(0)) {
case '+':
stack.addFirst(operandTwo + operandOne);
break;
case '-':
stack.addFirst(operandTwo - operandOne);
break;
case '*':
stack.addFirst(operandTwo * operandOne);
break;
case '/':
stack.addFirst(operandTwo / operandOne);
break;
} }else {
stack.addFirst(Double.parseDouble(currString));
}
}
return stack.removeFirst();
}
public static void main(String[] args) {
// TODO Auto-generated method stub
try {
String infix = "100+8*5-(10/2)*5+10.5";
double result = computePostfix(infix);
System.out.println(result);
} catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}
} }

(完)

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