Hive高阶聚合函数 GROUPING SETS、Cube、Rollup

时间:2023-03-10 07:38:39
Hive高阶聚合函数 GROUPING SETS、Cube、Rollup
-- GROUPING SETS作为GROUP BY的子句,允许开发人员在GROUP BY语句后面指定多个统计选项,可以简单理解为多条group by语句通过union all把查询结果聚合起来结合起来。
select
device_id
,os_id
,app_id
,count(user_id)
from test_xinyan_reg
group by device_id,os_id,app_id
grouping sets((device_id),(os_id),(device_id,os_id),())
-- 等价于
SELECT device_id,null,null,count(user_id) FROM test_xinyan_reg group by device_id UNION ALL
SELECT null,os_id,null,count(user_id) FROM test_xinyan_reg group by os_id UNION ALL
SELECT device_id,os_id,null,count(user_id) FROM test_xinyan_reg group by device_id,os_id UNION ALL
SELECT null,null,null,count(user_id) FROM test_xinyan_reg
; -- cube简称数据魔方,可以实现hive多个任意维度的查询,cube(a,b,c)则首先会对(a,b,c)进行group by,然后依次是(a,b),(a,c),(a),(b,c),(b),©,最后在对全表进行group by,他会统计所选列中值的所有组合的聚合
-- cube即为grouping sets的简化过程函数
select device_id,os_id,app_id,client_version,from_id,count(user_id)
from test_xinyan_reg
group by device_id,os_id,app_id,client_version,from_id with cube; -- rollup可以实现从右到做递减多级的统计,显示统计某一层次结构的聚合。
select device_id,os_id,app_id,client_version,from_id,count(user_id)
from test_xinyan_reg
group by device_id,os_id,app_id,client_version,from_id with rollup;
select
id
,name
,count(age)
from (
select 1 as id, 'a' as name,11 as age union all
select 2 as id, 'b' as name,12 as age union all
select 3 as id, 'c' as name,13 as age union all
select 4 as id, 'd' as name,14 as age union all
select 4 as id, 'd' as name,15 as age union all
select 4 as id, 'd' as name,16 as age union all
select 4 as id, 'd' as name,17 as age union all
select 4 as id, 'd' as name,18 as age
) t1
group by
id
,name
with cube
;
+------------+------------+------------+
| id | name | _c2 |
+------------+------------+------------+
| NULL | NULL | 8 |
| NULL | a | 1 |
| NULL | b | 1 |
| NULL | c | 1 |
| NULL | d | 5 |
| 1 | NULL | 1 |
| 1 | a | 1 |
| 2 | NULL | 1 |
| 2 | b | 1 |
| 3 | NULL | 1 |
| 3 | c | 1 |
| 4 | NULL | 5 |
| 4 | d | 5 |
+------------+------------+------------+ select
id
,name
,count(age)
from (
select 1 as id, 'a' as name,11 as age union all
select 2 as id, 'b' as name,12 as age union all
select 3 as id, 'c' as name,13 as age union all
select 4 as id, 'd' as name,14 as age union all
select 4 as id, 'd' as name,15 as age union all
select 4 as id, 'd' as name,16 as age union all
select 4 as id, 'd' as name,17 as age union all
select 4 as id, 'd' as name,18 as age
) t1
group by
id
,name
with rollup
;
+------------+------------+------------+
| id | name | _c2 |
+------------+------------+------------+
| NULL | NULL | 8 |
| 1 | NULL | 1 |
| 1 | a | 1 |
| 2 | NULL | 1 |
| 2 | b | 1 |
| 3 | NULL | 1 |
| 3 | c | 1 |
| 4 | NULL | 5 |
| 4 | d | 5 |
+------------+------------+------------+

ref: https://blog.****.net/qq_31573519/article/details/89054136