链接:http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1231
一个得分合法等价于前k小的得分之和大于等于$\frac{k*(k-1)}{2}$
听说是竞赛图的经典结论,可是我不会证。
#include<cstdio>
#include<cstring>
#include<algorithm>
#define w(x) (x)*(x-1)/2
using namespace std; int read_p,read_ca,read_f;
inline int read(){
read_p=;read_ca=getchar();read_f=;
while(read_ca<''||read_ca>'') {if (read_ca=='-') read_f=-;read_ca=getchar();}
while(read_ca>=''&&read_ca<='') read_p=read_p*+read_ca-,read_ca=getchar();
return read_p*read_f;
}
const int MOD=1e9+;
int T,n,m,mmh[][][],a,t[],q[],C[][];
inline void M(int &x){while(x>=MOD)x-=MOD;}
int main(){
register int i,j,k,l;
T=read();
C[][]=;
for (i=;i<=;i++)
for (C[i][]=,j=;j<=i;j++) M(C[i][j]=C[i-][j]+C[i-][j-]);
while (T--){
n=read();
memset(mmh,,sizeof(mmh));memset(t,,sizeof(t));
for (i=;i<n;i++){
a=read();
if (a!=-) t[a]++;else t[n]++;
}
if (t[]>) {puts("");continue;}
if (t[]==) if (mmh[][][]=,t[n]) mmh[][][]=C[t[n]][];
if (t[]==) mmh[][][]=;q[]=t[];
for (i=;i<n;i++) q[i]=q[i-]+t[i];
for (i=;i<=n;i++)
for (j=;j<n;j++)
for (k=;k<=n*n;k++)
if (mmh[i][j-][k]){
for (l=;l<=t[j];l++) if (k+j*l<w(i+l)) break;
if (l<=t[j]) continue;
for (l=t[j];l<=q[j]+t[n]-i;l++)
if (k+j*l>=w(i+l)) M(mmh[i+l][j][k+j*l]+=1LL*mmh[i][j-][k]*C[t[n]-(i-q[j-])][l-t[j]]%MOD);
}
printf("%d\n",mmh[n][n-][w(n)]);
}
}