How do I replace foo. with foo_ with sed simply running
我该如何替换foo。用foo_和sed一起运行
sed 's/foo./foo_/g' file.php
doesn't work. Thanks!
不起作用。谢谢！
5 个解决方案
#1
18
Escape the .:
逃离。：
sed 's/foo\./foo_/g' file.php
sed's / foo \ ./ foo_ / g'file.php
Example:
例：
~$ cat test.txt
foo.bar
~$ sed 's/foo\./foo_/g' test.txt
foo_bar
#2
6
Escape the dot with a \
用一个\逃脱点
sed 's/foo\./foo_/g' file.php
If you find the combination of / and \ confusing you can use another 'separator' character
如果您发现/和\ confusing的组合，您可以使用另一个'分隔符'字符
sed 's#foo\.#foo_#g
The 2nd character after the s can be anything and sed will use that character as a separator.
s之后的第二个字符可以是任何东西，sed将使用该字符作为分隔符。
#3
6
Interestingly, if you want to search for and replace just the dot, you have to put the dot in a character set. Escaping just the dot alone in a sed command for some reason doesn't work. The dot is still expanded to a single character wild card.
有趣的是，如果您只想搜索并替换点，则必须将点放在字符集中。出于某种原因，仅在sed命令中单独转义点不起作用。点仍然扩展为单个字符外卡。
$ bash --version # Ubuntu Lucid (10.04)
GNU bash, version 4.1.5(1)-release (x86_64-pc-linux-gnu)
GNU bash，版本4.1.5（1）-release（x86_64-pc-linux-gnu）
$ echo aa.bb.cc | sed s/\./-/g # replaces all characters with dash
'--------'
'--------'
$ echo aa.bb.cc | sed s/[.]/-/g # replaces the dots with a dash
aa-bb-cc
AA-BB-CC
With the addition of leading characters in the search, the escape works.
通过在搜索中添加前导字符，逃生工作。
$ echo foo. | sed s/foo\./foo_/g # works
foo_
foo_
Putting the dot in a character set of course also works.
将点放在字符集当然也有效。
$ echo foo. | sed s/foo[.]/foo_/g # also works
foo_
foo_
-- Paul
- 保罗
#4
3
You need to escape the dot - an unescaped dot will match any character after foo.
你需要逃离点 - 未转义的点将匹配foo之后的任何角色。
sed 's/foo\./foo_/g'
#5
0
For myself, sed 's/foo\./foo_/g' is working. But you can also try:
对我自己来说，sed's / foo \ ./ foo_ / g'正在运行。但你也可以尝试：
sed -e 's/foo\./foo_/g'
and
和
sed -e "s/foo\\./foo_/g"
and
和
sed 's/foo[.]/foo_/g'
#1
18
Escape the .:
逃离。：
sed 's/foo\./foo_/g' file.php
sed's / foo \ ./ foo_ / g'file.php
Example:
例：
~$ cat test.txt
foo.bar
~$ sed 's/foo\./foo_/g' test.txt
foo_bar
#2
6
Escape the dot with a \
用一个\逃脱点
sed 's/foo\./foo_/g' file.php
If you find the combination of / and \ confusing you can use another 'separator' character
如果您发现/和\ confusing的组合，您可以使用另一个'分隔符'字符
sed 's#foo\.#foo_#g
The 2nd character after the s can be anything and sed will use that character as a separator.
s之后的第二个字符可以是任何东西，sed将使用该字符作为分隔符。
#3
6
Interestingly, if you want to search for and replace just the dot, you have to put the dot in a character set. Escaping just the dot alone in a sed command for some reason doesn't work. The dot is still expanded to a single character wild card.
有趣的是，如果您只想搜索并替换点，则必须将点放在字符集中。出于某种原因，仅在sed命令中单独转义点不起作用。点仍然扩展为单个字符外卡。
$ bash --version # Ubuntu Lucid (10.04)
GNU bash, version 4.1.5(1)-release (x86_64-pc-linux-gnu)
GNU bash，版本4.1.5（1）-release（x86_64-pc-linux-gnu）
$ echo aa.bb.cc | sed s/\./-/g # replaces all characters with dash
'--------'
'--------'
$ echo aa.bb.cc | sed s/[.]/-/g # replaces the dots with a dash
aa-bb-cc
AA-BB-CC
With the addition of leading characters in the search, the escape works.
通过在搜索中添加前导字符，逃生工作。
$ echo foo. | sed s/foo\./foo_/g # works
foo_
foo_
Putting the dot in a character set of course also works.
将点放在字符集当然也有效。
$ echo foo. | sed s/foo[.]/foo_/g # also works
foo_
foo_
-- Paul
- 保罗
#4
3
You need to escape the dot - an unescaped dot will match any character after foo.
你需要逃离点 - 未转义的点将匹配foo之后的任何角色。
sed 's/foo\./foo_/g'
#5
0
For myself, sed 's/foo\./foo_/g' is working. But you can also try:
对我自己来说，sed's / foo \ ./ foo_ / g'正在运行。但你也可以尝试：
sed -e 's/foo\./foo_/g'
and
和
sed -e "s/foo\\./foo_/g"
and
和
sed 's/foo[.]/foo_/g'