题解:
同bzoj1717
代码:
#include<bits/stdc++.h>
using namespace std;
const int P1=,P2=,P=;
int a1[P],num[P],a2[P],flag[P],a[P],inv1[P],inv2[P],n,m;
int find(int x,int y)
{
int k=(long long)x*y%P;
for (;flag[k]&&(a1[k]!=x||a2[k]!=y);k=(k+)%P);
return k;
}
int pd(int x)
{
memset(a1,,sizeof a1);
memset(a2,,sizeof a2);
memset(flag,,sizeof flag);
memset(num,,sizeof num);
inv1[]=inv2[]=;
for (int i=;i<=n;i++)inv1[i]=inv1[i-]*%P1,inv2[i]=inv2[i-]*%P2;
int p1=,p2=;
for (int i=;i<=n;i++)
{
p1=(p1*+a[i])%P1;
p2=(p2*+a[i])%P2;
if (i>x)
{
p1=(p1-(long long)a[i-x]*inv1[x]%P1+P1)%P1;
p2=(p2-(long long)a[i-x]*inv2[x]%P2+P2)%P2;
}
if (i<x)continue;
int l=find(p1,p2);
a1[l]=p1;a2[l]=p2;flag[l]=;
num[l]++;
if (num[l]>=m)return ;
}
return ;
}
int main()
{
scanf("%d%d",&n,&m);
for (int i=;i<=n;i++)scanf("%d",&a[i]);
int l=,r=n;
while (l<r)
{
int mid=(l+r+)/;
if (pd(mid))l=mid;
else r=mid-;
}
printf("%d\n",l);
}