Python3处理文件中每个词的方法

时间:2022-06-29 02:12:45

本文实例讲述了Python3处理文件中每个的方法。分享给大家供大家参考。具体实现方法如下:

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'''''
Created on Dec 21, 2012
处理文件中的每个词
@author: liury_lab
'''
import codecs
the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8')
for line in the_file:
  for word in line.split():
    print(word, end = "|")
the_file.close()
# 若词的定义有变,可使用正则表达式
# 如词被定义为数字字母,连字符或单引号构成的序列
import re
the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8')
print()
print('************************************************************************')
re_word = re.compile('[\w\'-]+')
for line in the_file:
  for word in re_word.finditer(line):
    print(word.group(0), end = "|")
the_file.close()
# 封装成迭代器
def words_of_file(file_path, line_to_words = str.split):
  the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8')
  for line in the_file:
    for word in line_to_words(line):
      yield word
  the_file.close()
print()
print('************************************************************************')
for word in words_of_file('d:/text.txt'):
  print(word, end = '|')
def words_by_re(file_path, repattern = '[\w\'-]+'):
  the_file = codecs.open('d:/text.txt', 'rU', 'UTF-8')
  re_word = re.compile('[\w\'-]+')
 
  def line_to_words(line):
    for mo in re_word.finditer(line):
      yield mo.group(0) # 原书为return,发现结果不对,改为yield
  return words_of_file(file_path, line_to_words)
print()
print('************************************************************************')
for word in words_by_re('d:/text.txt'):
  print(word, end = '|')

希望本文所述对大家的Python程序设计有所帮助。