The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker's personality. Such a preference is called "Kuchiguse" and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle "nyan~" is often used as a stereotype for characters with a cat-like personality:
Itai nyan~ (It hurts, nyan~)
Ninjin wa iyada nyan~ (I hate carrots, nyan~)
Now given a few lines spoken by the same character, can you find her Kuchiguse?
Input Specification:
Each input file contains one test case. For each case, the first line is an integer N (2). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character's spoken line. The spoken lines are case sensitive.
Output Specification:
For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write nai.
Sample Input 1:
3
Itai nyan~
Ninjin wa iyadanyan~
uhhh nyan~
Sample Output 1:
nyan~
Sample Input 2:
3
Itai!
Ninjinnwaiyada T_T
T_T
Sample Output 2:
nai题意：
题意是寻找一组字符串中最大相同后缀，并输出。如果没有：则输出‘nai’
题解：
简单题，可以reverse反转一下找最大前缀
AC代码：
#include<bits/stdc++.h>
using namespace std;
string a[];
int main(){
int n;
cin>>n;
getchar();
for(int i=;i<=n;i++){
getline(cin,a[i]);
reverse(a[i].begin(),a[i].end());
//cout<<a[i]<<endl;
}
string s="";
int f=;
char c;
for(int i=;i<;i++){
for(int j=;j<=n;j++){
if(i>=a[j].length()){
f=;
break;
}
if(j>=){
if(a[j][i]!=a[][i]){
f=;
break;
}
}else{
c=a[][i];
}
}
if(f==){
s+=c;
}
}
reverse(s.begin(),s.end());
if(s!="") cout<<s;
else cout<<"nai";
return ;
}