题意:
给定一棵树,对树有3e5的操作,每次操作为,把树上某个节点的不超过d的子节点都加上值x;
思路:
多开一个vector记录每个点上的操作。dfs这颗树,同时以深度开一个树状数组,踩到u节点的时候,给数组add(deep, x); add(min(maxn,deep + op[u][i].fi + 1), - op[u][i].se);
搜索下去,反回前得到这个节点的答案,并消去这个点的影响。
//#pragma GCC optimize(3)
//#pragma comment(linker, "/STACK:102400000,102400000") //c++
// #pragma GCC diagnostic error "-std=c++11"
// #pragma comment(linker, "/stack:200000000")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include <algorithm>
#include <iterator>
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <iomanip>
#include <bitset>
#include <cctype>
#include <cstdio>
#include <string>
#include <vector>
#include <stack>
#include <cmath>
#include <queue>
#include <list>
#include <map>
#include <set>
#include <cassert> using namespace std;
#define lson (l , mid , rt << 1)
#define rson (mid + 1 , r , rt << 1 | 1)
#define debug(x) cerr << #x << " = " << x << "\n";
#define pb push_back
#define pq priority_queue typedef long long ll;
typedef unsigned long long ull;
//typedef __int128 bll;
typedef pair<ll ,ll > pll;
typedef pair<int ,int > pii;
typedef pair<int,pii> p3; //priority_queue<int> q;//这是一个大根堆q
//priority_queue<int,vector<int>,greater<int> >q;//这是一个小根堆q
#define fi first
#define se second
//#define endl '\n' #define OKC ios::sync_with_stdio(false);cin.tie(0)
#define FT(A,B,C) for(int A=B;A <= C;++A) //用来压行
#define REP(i , j , k) for(int i = j ; i < k ; ++i)
#define max3(a,b,c) max(max(a,b), c);
//priority_queue<int ,vector<int>, greater<int> >que; const ll mos = 0x7FFFFFFF; //
const ll nmos = 0x80000000; //-2147483648
const int inf = 0x7f7f7f7f;
const ll inff = 0x3f3f3f3f3f3f3f3f; //
const int mod = 1e8+;
const double esp = 1e-;
const double PI=acos(-1.0);
const double PHI=0.61803399; //黄金分割点
const double tPHI=0.38196601; template<typename T>
inline T read(T&x){
x=;int f=;char ch=getchar();
while (ch<''||ch>'') f|=(ch=='-'),ch=getchar();
while (ch>=''&&ch<='') x=x*+ch-'',ch=getchar();
return x=f?-x:x;
} /*-----------------------showtime----------------------*/ const int maxn = 3e5+;
ll ans[maxn];
vector<pii> op[maxn];
vector<int>mp[maxn];
ll sum[maxn]; int lowbit(int x){
return x & (-x);
} void add(int x,int val){
while(x < maxn){
sum[x] += val;
x += lowbit(x);
}
} ll getsum(int x){
ll res = ;
while(x > ){
res += sum[x];
x -= lowbit(x);
}
return res;
}
void dfs(int u, int fa, int deep){ for(int i=; i<op[u].size(); i++){
add(deep, op[u][i].se);
add(min(maxn,deep + op[u][i].fi + ), -1ll*op[u][i].se);
} for(int i=; i<mp[u].size(); i++){
int v = mp[u][i];
if(v == fa)continue;
dfs(v, u, deep + );
} ans[u] = getsum(deep); for(int i=; i<op[u].size(); i++){
add(deep, -1ll*op[u][i].se);
add(min(maxn,deep + op[u][i].fi + ), op[u][i].se);
}
}
int main(){ int n,m; scanf("%d", &n);
for(int i=; i<n; i++){
int u,v;
scanf("%d%d", &u, &v);
mp[u].pb(v);
mp[v].pb(u);
}
scanf("%d", &m);
for(int i=; i<=m; i++){
int v,d,x;
scanf("%d%d%d", &v, &d, &x);
op[v].pb(pii(d,x));
} dfs(, -, );
for(int i=; i<=n; i++) printf("%lld ", ans[i]);
puts("");
return ;
}
CFeduE