public class Solution
{
public int FindShortestSubArray(int[] nums)
{
//先找到最大频度的数字都有哪些,加入到一个集合中
var dic = new Dictionary<int, int>();
var dic2 = new Dictionary<int, List<int>>();
for (int i = ; i < nums.Length; i++)
{
var num = nums[i];
if (!dic.ContainsKey(num))
{
dic.Add(num, );
dic2.Add(num, new List<int>());
}
else
{
dic[num]++;
} dic2[num].Add(i);//记录此数字的所有下标 }
var list = dic.OrderByDescending(x => x.Value).ToList();
int maxFreq = list[].Value;
var list2 = dic.Where(x => x.Value == maxFreq).ToList(); //遍历集合,一次判断每个数最早出现的位置和最晚出现的位置
int min = int.MaxValue;
foreach (var l in list2)
{
var num = l.Key;
var begin = dic2[num].First();
var end = dic2[num].Last();
var dif = end - begin;
if (min > dif)
{
min = dif;
}
}
//寻找最小间隔
return min + ;
}
}