coroutine:
stackless和stackful
jmp
基于switch的trick:
http://www.chiark.greenend.org.uk/~sgtatham/coroutines.html
文中提到高德纳另有一套办法.
#define crBegin static int state=0; switch(state) { case 0:
#define crReturn(x) do { state=__LINE__; return x; \
case __LINE__:; } while (0)
#define crFinish } int function(void) {
static int i;
crBegin;
for (i = 0; i < 10; i++)
crReturn(i);
crFinish;
}