url携带的参数获取并处理demo

时间:2023-03-09 07:52:16
url携带的参数获取并处理demo

url demo:

http://servername/webname/pagename.csp?paramName=paramValue&paramName2=paramName2&paramName3=paramName3

获取其中的参数:

String parameter = request.getQueryString();//只适用get请求

对参数的分割处理:

public static Map<String,String> getQueryParams(String parameter) {
try {
Map<String, String> params = new HashMap<String, String>(); for (String param : parameter.split("&")) {
String[] pair = param.split("=");
String key = URLDecoder.decode(pair[0], "UTF-8");
String value = "";
if (pair.length > 1) {
value = URLDecoder.decode(pair[1], "UTF-8");
}
params.put(key, value); } return params;
} catch (UnsupportedEncodingException ex) {
throw new AssertionError(ex);
}
}