Java Regex match IP address

时间:2023-03-09 02:33:59
Java Regex match IP address

Reference:

[1] https://www.mkyong.com/regular-expressions/how-to-validate-ip-address-with-regular-expression/

import java.util.regex.Matcher;
import java.util.regex.Pattern; public class IPAddressValidator{ private Pattern pattern;
private Matcher matcher; private static final String IPADDRESS_PATTERN =
"^([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])\\." +
"([01]?\\d\\d?|2[0-4]\\d|25[0-5])$"; public IPAddressValidator(){
pattern = Pattern.compile(IPADDRESS_PATTERN);
} /**
* Validate ip address with regular expression
* @param ip ip address for validation
* @return true valid ip address, false invalid ip address
*/
public boolean validate(final String ip){
matcher = pattern.matcher(ip);
return matcher.matches();
}
}

Description

^		#start of the line
( # start of group #1
[01]?\\d\\d? # Can be one or two digits. If three digits appear, it must start either 0 or 1
# e.g ([0-9], [0-9][0-9],[0-1][0-9][0-9])
| # ...or
2[0-4]\\d # start with 2, follow by 0-4 and end with any digit (2[0-4][0-9])
| # ...or
25[0-5] # start with 2, follow by 5 and ends with 0-5 (25[0-5])
) # end of group #2
\. # follow by a dot "."
.... # repeat with 3 times (3x)
$ #end of the line

Whole combination means, digit from 0 to 255 and follow by a dot “.”, repeat 4 time and ending with no dot “.” Valid IP address format is “0-255.0-255.0-255.0-255”