题目:
Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
提示:
此题要求判断一个给定的二叉树是否是“平衡”的,这里“平衡”的定义是要求每个节点的左右两颗子树高度之差不能大于1,解题的思想是使用DFS。
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isBalanced(TreeNode* root) {
return dfs(root) != -;
}
int dfs(TreeNode* root) {
if (root == NULL) return ;
int left = dfs(root->left);
if (left == -) return -;
int right = dfs(root->right);
if (right == -) return -; if (abs(left - right) > ) return -;
return max(left, right) + ;
}
};