Description
Given number n. Print number from 1 to n. But:
- when number is divided by 3, print "fizz".
- when number is divided by 5, print "buzz".
- when number is divided by both 3 and 5, print "fizz buzz".
Example
If n = 15
, you should return:
[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]
Challenge
Can you do it with only one if statement?
public class Solution {
/**
* @param n: An integer
* @return: A list of strings.
*/
public List<String> fizzBuzz(int n) {
// write your code here
List<String> res = new ArrayList<>();
for(int i=1;i<n+1;i++){
if(i % 15 == 0){
res.add("fizz buzz");
}else if( i % 3 ==0){
res.add("fizz");
}else if( i % 5 == 0){
res.add("buzz");
}else{
res.add(i + "");
}
}
return res;
}
}
描述
给你一个整数n. 从 1 到 n 按照下面的规则打印每个数:
如果这个数被3整除,打印fizz.
如果这个数被5整除,打印buzz.
如果这个数能同时被3和5整除,打印fizz buzz.
您在真实的面试中是否遇到过这个题?
样例
比如 n = 15, 返回一个字符串数组:
[
"1", "2", "fizz",
"4", "buzz", "fizz",
"7", "8", "fizz",
"buzz", "11", "fizz",
"13", "14", "fizz buzz"
]