C++解析命令行参数(仿C语言args)

时间:2023-03-09 00:35:30
C++解析命令行参数(仿C语言args)

说好不造*的,就管不住这手

#include <cstdio>
#include <string>
#include <vector> bool ParseChar( const std::string& buf, std::size_t& pos, char& ch, bool& escape )
{
char c; if ( pos == buf.length() )
return false; // Get the character to parse
c = buf.at( pos++ ); if ( c == '\\' )
{
// Parse the escape character if ( pos != buf.length() )
{
// Get the character to escape
c = buf.at( pos++ ); if ( c == '\\' || c == '"' )
{
ch = c;
escape = true;
}
else
{
// Does not support the character, just hold the '\\' character
// We need move the POS back to prepare for the character parsing
pos--;
ch = '\\';
escape = false;
}
}
else
{
// We can't get the character to escape
// Just hold the '\\' character
ch = c;
escape = false;
}
}
else
{
// Copy the character ch = c;
escape = false;
} return true;
} bool ParseToken( const std::string& buf, std::size_t& pos, std::string& token )
{
char c {};
bool escape {};
bool quote {}; // True if parsing a string
bool doing {}; // True if parsing has started // Skip blank characters, if any
while ( pos != buf.length() )
{
c = buf.at( pos ); if ( c != ' ' && c != '\t' )
break; pos++;
} // Clean up the token
token.clear(); while ( ParseChar( buf, pos, c, escape ) )
{
if ( !doing )
{
// Parse the first character if ( c == '"' && !escape )
{
// Just mark the beginning of the string, don't copy it
quote = true;
}
else
{
// Copy the first character of the token
token.push_back( c );
} // '\n' is a single character token
if ( c == '\n' )
return true; // We have parsed any one character, the parsing has started
doing = true;
}
else
{
if ( quote )
{
// Copying the character of the string here if ( c == '"' && !escape )
{
// Mark the ending of a string
return true;
}
else
{
// Copy the character of the string
token.push_back( c );
}
}
else
{
// Copying the character of the token here if ( c == '"' && !escape )
{
// We accidentally encounter a string beginning mark before the token finished
// We need to finish the token and move the POS back to prepare for the string parsing
pos--;
return true;
} if ( c == '\n' )
{
// We accidentally encounter a '\n' before the token finished
// We need to finish the token and move the POS back to prepare for the '\n' parsing
pos--;
return true;
} if ( c == ' ' || c == '\t' )
{
// Mark the ending of a string
return true;
}
else
{
// Copy the character of the token
token.push_back( c );
}
}
}
} // If no any characters are parsed, we are at the end of the buffer
// returns 'false' to finish the parsing return doing;
} int main()
{
std::string cmdline = R"( connect
spawn
name "Billy Herrington"
flags 0xffff ""
desc "boy \\next\" door" )"; std::size_t pos {};
std::string token {}; while ( ParseToken( cmdline, pos, token ) )
{
printf_s( "[%s]\n", token == "\n" ? "\\n" : token.c_str() );
} return ;
}

输出如下

[connect]
[\n]
[spawn]
[1]
[\n]
[name]
[Billy Herrington]
[\n]
[flags]
[0xffff]
[]
[\n]
[desc]
[boy \next" door]

我对换行符做了点特殊处理,如果不需要可以删掉相关的判断代码