题目
给定一个无向图的节点,克隆能克隆的一切
思路
1--2
|
3--5
以上图为例,
node neighbor
1 2, 3
2 1
3 1, 5
5 3
首先从1开始, 将(node,newNode)put到HashMap中
node newNode
1 1
然后遍历该node的所有neighbor
node neighbor
1 2, 3
此时遍历到2
将(node,newNode)put到HashMap中
node newNode
1 1 -- 2 // newNode.neighbors.add(clone)
2 2
代码
public class Solution { Map<UndirectedGraphNode, UndirectedGraphNode> map = new HashMap<>(); public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) {
return null;
} //DFS
if (map.containsKey(node)) {
return map.get(node);
} UndirectedGraphNode newNode = new UndirectedGraphNode(node.label);
map.put(node, newNode);
for (UndirectedGraphNode nei : node.neighbors) {
UndirectedGraphNode clone = cloneGraph(nei);
newNode.neighbors.add(clone);
}
return newNode;
}
}