idsArr = [ "id12345", "id27891", "id98654"]
idsNameIntvalueArr = [["id22913", "Peter Parker", 15], ["id12345", "Donald Duck", 6], ["id98654", "Mickey Mouse", 9], ["id112233", "Lion King", 9]]
I'm new in Swift, please give me advice, what is the best practice to compare this 2 arrays by id, if id matches, need to make new array with "name" and Int value, in this case:
我是Swift的新手，请给我建议，用ID比较这2个数组的最佳做法是什么，如果id匹配，需要用“name”和Int值创建新数组，在这种情况下：
resultArr = [["Donald Duck", 6],["Mickey Mouse", 9]]
Thanks.
谢谢。
1 个解决方案
#1
1
You can do that like this:
你可以这样做：
let resultArr = idsNameIntvalueArr.filter({ idsArr.contains($0[0] as! String) }).map({ [$0[1], $0[2]] })
First, you need to filter the array to include only the members whose IDs exists in idsArr.
首先，您需要过滤数组以仅包含其ID存在于idsArr中的成员。
Then, after filtering the array you need to create sub-arrays that contains only the name and age, and this is what map does.
然后，在过滤数组之后，您需要创建仅包含名称和年龄的子数组，这就是地图的作用。
#1
1
You can do that like this:
你可以这样做：
let resultArr = idsNameIntvalueArr.filter({ idsArr.contains($0[0] as! String) }).map({ [$0[1], $0[2]] })
First, you need to filter the array to include only the members whose IDs exists in idsArr.
首先，您需要过滤数组以仅包含其ID存在于idsArr中的成员。
Then, after filtering the array you need to create sub-arrays that contains only the name and age, and this is what map does.
然后，在过滤数组之后，您需要创建仅包含名称和年龄的子数组，这就是地图的作用。