UVA 1513 - Movie collection(树状数组)

时间:2025-04-02 22:36:25

UVA 1513 - Movie collection

option=com_onlinejudge&Itemid=8&page=show_problem&category=502&problem=4259&mosmsg=Submission+received+with+ID+13965699" target="_blank" style="">题目链接

题意:有一些光盘,一開始是n-1叠上去的(1最顶),如今每次抽出一张,要问这一张上面有多少张,然后把抽出来这张放到最顶,输出每次询问

思路:树状数组,数组维护每一个位置以下有多少张光碟,这样每次拿出一张,就在对应位置-1就能够了,然后在最顶位置上多一个位置+1

代码:

#include <cstdio>
#include <cstring> #define lowbit(x) (x&(-x))
const int N = 200005;
int t, n, m, arr[N], bit[N]; void add(int x, int v) {
while (x < N) {
bit[x] += v;
x += lowbit(x);
}
} int query(int x) {
int ans = 0;
while (x) {
ans += bit[x];
x -= lowbit(x);
}
return ans;
} int main() {
scanf("%d", &t);
while (t--) {
memset(bit, 0, sizeof(bit));
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; i++) {
arr[i] = n + 1 - i;
add(i, 1);
}
int v;
for (int i = 1; i <= m; i++) {
scanf("%d", &v);
int under = query(arr[v]);
printf("%d%c", n - under, i == m ? '\n' : ' ');
add(arr[v], -1);
arr[v] = n + i;
add(n + i, 1);
}
}
return 0;
}