问题:对字符串中的文本做查找和替换
解决方案:
1、对于简单模式:str.replace(old, new[, max])
2、复杂模式:使用re模块中的re.sub(匹配的模式, newstring, oldstring[,替换个数])函数
3、re.subn()可以获得替换的总次数
# example.py
#
# Examples of simple regular expression substitution import re #simple sample
text1='yeah,but no,but yeah,but no,but yeah,but no,but yeah'
print (text1.replace('yeah','yeh'))
print (text1.replace('no','yes',2))
print ('---------------------------')
# Some sample text
text = 'Today is 11/27/2012. PyCon starts 3/13/2013.'
datepat = re.compile(r'(\d+)/(\d+)/(\d+)')
# (a) Simple substitution \3-表示匹配的模式中第3个模式组
print(datepat.sub(r'\3-\1-\2', text)) #等价于print (re.sub(r'(\d+)/(\d+)/(\d+)',r'\3-\1-\2', text))
print ('*****************************')
# (b) Replacement function 替换回调函数
from calendar import month_abbr
def change_date(m):
mon_name = month_abbr[int(m.group(1))]
return '{} {} {}'.format(m.group(2), mon_name, m.group(3)) print(datepat.sub(change_date, text))
print (re.sub(r'(\d+)/(\d+)/(\d+)',change_date, text))
print ('++++++++++++++++++++++++++++++++')
# 通过re.subn()获取替换的总次数
newtext,n=datepat.subn(r'\3-\1-\2', text)
print (newtext)
print (n)
>>> ================================ RESTART ================================
>>>
yeh,but no,but yeh,but no,but yeh,but no,but yeh
yeah,but yes,but yeah,but yes,but yeah,but no,but yeah
---------------------------
Today is 2012-11-27. PyCon starts 2013-3-13.
*****************************
Today is 27 Nov 2012. PyCon starts 13 Mar 2013.
Today is 27 Nov 2012. PyCon starts 13 Mar 2013.
++++++++++++++++++++++++++++++++
Today is 2012-11-27. PyCon starts 2013-3-13.
2
>>>