java和js中JSONObject,JSONArray,Map,String之间转换

时间:2023-01-06 08:48:44

--------------------------------------------------Java中--------------------------------------------------------------

1.String转JSONObject

(1).

String jsonMessage = "{\"语文\":\"88\",\"数学\":\"78\",\"计算机\":\"99\"}";

JSONObject  myJson = JSONObject.fromObject(jsonMessage);

(2).用阿里巴巴的fastjson的jar包

String str = "{\"baid\":null,\"32d3:\":\"null\",433:\"0x32\",032:\"ju9fw\"}";
com.alibaba.fastjson.JSONObject jm = com.alibaba.fastjson.JSON.parseObject(str);

2.String转JSONArray

String jsonMessage = "[{'num':'成绩', '外语':88, '历史':65, '地理':99, 'object':{'aaa':'1111','bbb':'2222','cccc':'3333'}}," +
          "{'num':'兴趣', '外语':28, '历史':45, '地理':19, 'object':{'aaa':'11a11','bbb':'2222','cccc':'3333'}}," +
          "{'num':'爱好', '外语':48, '历史':62, '地理':39, 'object':{'aaa':'11c11','bbb':'2222','cccc':'3333'}}]";
 JSONArray myJsonArray = JSONArray.fromObject(jsonMessage);
 System.out.println(myJsonArray);

3.String转Map

(1)

String jsonMessage = "{\"语文\":\"88\",\"数学\":\"78\",\"计算机\":\"99\"}";

JSONObject  myJson = JSONObject.fromObject(jsonMessage);

Map m = myJson; 

(2)用阿里巴巴的fastjson的jar包

String str = "{\"baid\":null,\"32d3:\":\"null\",433:\"0x32\",032:\"ju9fw\"}";
Map mapTypes = com.alibaba.fastjson.JSON.parseObject(str);

(3) (需要引入jackjson的core、databind、annotations三个jar包  )

String json = "{\"PayPal key2\":\"PayPal value2\",\"PayPal key1\":\"PayPal value1\",\"PayPal key3\":\"PayPalvalue3\"}";  

ObjectMapper mapper = new ObjectMapper();    
 Map<String,Object> m = mapper.readValue(json, Map.class);  

(4)(特殊格式的String)

String a ="{se=2016, format=xml, at=en co=3}";

a =  a.substring(1, a.length()-1);
Map docType = new HashMap();  
Java.util.StringTokenizer items;  
for(StringTokenizer entrys = new StringTokenizer(a, ", ");entrys.hasMoreTokens();   
docType.put(items.nextToken(), items.hasMoreTokens() ? ((Object) (items.nextToken())) : null)){  
     items = new StringTokenizer(entrys.nextToken(), "=");  
   }

 

4.JSONObject、JSONArray,Map转String

JSONObject——String:

System.out.println(myJsonObject);//可直接输出JSONObject的内容

myJsonObject.toString();

JSONArray——String:

System.out.println(myJsonArray);//可直接输出myJsonArray的内容

myJsonArray.toString();

Map——String:

System.out.println(map);//可直接输出map的内容

map.toString();

 

5.JSONObject转JSONArray

 

 

6.JSONObject转Map

JSONObject  myJson = JSONObject.fromObject(jsonString);

Map m = myJson; 

 

7.JSONArray转JSONObject

  for(int i=0 ; i < myJsonArray.length() ;i++)
   {
    //获取每一个JsonObject对象
    JSONObject myjObject = myJsonArray.getJSONObject(i);

 

}

 

8.JSONArray转Map

 

 

9.Map转JSONObject

JSONObject json = JSONObject.fromObject( map );   

 

10.Map转JSONArray

   JSONArray.fromObject(map);

11.List转JSONArray

JSONArray jsonArray2 = JSONArray.fromObject( list );      

 

12.JSONArray转List

List<Map<String,Object>> mapListJson = (List)jsonArray;

 

13.String转数组

String string = "a,b,c";
String [] stringArr= string.split(",");  //注意分隔符是需要转译滴...
如果是"abc"这种字符串,就直接
String string = "abc" ;
char [] stringArr = string.toCharArray(); //注意返回值是char数组
如果要返回byte数组就直接使用getBytes方法就ok了~~
String string = "abc" ;
byte [] stringArr = string.getBytes();

数组转String

char[] data={a,b,c}; 
String s=new String(data); 

 

--------------------------------------------js中---------------------------------------

js中自定义的map请参考:http://blog.csdn.NET/superit401/article/details/72842469

 

1.json转Map(并获取key和value)

var str = JSON.stringify(json);

 str = '{ "10.10.11.1": { "target_1": "34.2","target_3": "70.83","target_2": "50.51"}}';
var map = eval("("+str+")");

//以下为获取Map的key-value:
for (var key in map) {  
var a = map[key];
for (var k in a) {  
alert(k+'---'+a[k]);
}   
  }  

参考:http://www.bkjia.com/webzh/899371.html

 

2.Map转json:

不能直接map转json:var mjson = JSON.parse(map);

也不能var mjson = $.parseJSON(map);//结果为null

只能分两步走:

var mstr = JSON.stringify(map);

var jsonstr = JSON.parse(mstr);

(注:有的浏览器不支持JSON.parse()方法,使用jQuery.parseJSON()方法时,在浏览器支持时会返回执行JSON.parse()方法的结果,否则会返回类似执行eval()方法的结果)

参考:http://www.jb51.net/article/87642.htm

3.json转String:

JSON.stringify(json);

 

4.String转json:

var str = '{ "10.10.11.1": { "target_1": "34.2","target_3": "70.83","target_2": "50.51"}}';

var jsonstr = JSON.parse(str);

 

5.Map转String:

var mstr = JSON.stringify(map);

6.String转Map:

var str = '{ "10.10.11.1": { "target_1": "34.2","target_3": "70.83","target_2": "50.51"}}';
var map = eval("("+str+")");

转至:http://blog.csdn.net/superit401/article/details/51727739