在C中包含通配符的目录列表

Is there a ready-made function in C that can list the contents of a directory using wildcards to filter out file names, for example, the equivalent of:

C中是否有现成的函数，可以使用通配符来列出目录的内容来过滤文件名，例如:

echo [!b]????

which shows the names of directory entries that are four characters long and do not start with "b"?

显示4个字符长且不以“b”开头的目录项的名称?

I know I can use scandir, but then, I need to provide my own filter function:

我知道我可以使用scandir，但是我需要提供我自己的过滤器功能:

#include <stdio.h>
#include <stdlib.h>
#include <dirent.h>
int filter(const struct dirent *entry)
{
    if (strlen(entry->d_name) == 4 && entry->d_name[0] != 'b') return 1;
    else return 0;
}
void main(void)
{
    struct dirent **list;
    int           count;
    count=scandir(".", &list, filter, alphasort)-1;
    if (count < 0)
        puts("Cannot open directory");
    else
        for (; count >= 0; count--)
            puts(list[count]->d_name);
    free(list);
}

Honestly, I am seriously considering actually calling shell to do it for me:

老实说，我正在认真地考虑打电话给壳牌公司帮我:

#include <stdio.h>
#include <stdlib.h>
void main(void)
{
    FILE *fp;
    char buffer[1024];
    fp=popen("echo [!b]???", "r");
    if (fp == NULL)
        puts("Failed to run command.");
    else
        while (fgets(buffer, sizeof(buffer), fp) != NULL)
            puts(buffer);
    pclose(fp);
}

1 个解决方案

#1

As mentioned in the comments the glob() function would be pretty good for this:

如评论中所提到的，glob()函数对这一点很有好处:

#include <stdio.h>
#include <glob.h>

int
main (void)
{
    int i=0;
    glob_t globbuf;

    if (!glob("[!b]????", 0, NULL, &globbuf)) {
        for (i=0;  i <globbuf.gl_pathc; i++) { 
            printf("%s ",globbuf.gl_pathv[i]);
        }
        printf("\n");
        globfree(&globbuf);
    } else 
        printf("Error: glob()\n");
}