Python Telnetlib read_until 'a'、'b'、'c'和'd'

When I connect to the telnet session using the telnetlib module, i need to wait for four strings: 'a', 'b', 'c' and 'd' or timeout (10 seconds) before I write a string to the socket.

当我使用telnetlib模块连接到telnet会话时，我需要等待4个字符串:'a'、'b'、'c'和'd'或超时(10秒)，然后才能向套接字写入字符串。

Is there a way to use tn.read_until('a','b','c','d', timeout)

是否有办法使用tn.read_until('a'，'b'，'c'，'d'，超时)

I just want to wait for all 4 strings to come first before action.

我只是想等待所有的4个字符串在操作之前先来。

Also these four strings comes in a different order every time. Thanks for any help.

这四根弦每次都以不同的顺序出现。感谢任何帮助。

1 个解决方案

#1

You can use the .expect method to wait for a, b, c or d

您可以使用.expect方法等待a、b、c或d

Telnet.expect(list[, timeout])

Telnet。期望(列表(超时))

Read until one from a list of a regular expressions matches.

从正则表达式匹配的列表中读取。

So:

所以:

(index, match, content_including_abcd) = tn.expect(['a', 'b', 'c', 'd'], timeout)

Returns (-1, None, current_buffer) when timeout is reached.

当到达超时时，返回(-1,None, current_buffer)。

We could easily change it to a loop to wait for a, b, c and d:

我们可以很容易地把它变成一个循环，等待a、b、c和d:

deadline = time.time() + timeout
remaining_strings = ['a', 'b', 'c', 'd']
total_content = ''
while remaining_strings:
    actual_timeout = deadline - time.time()
    if actual_timeout < 0:
        break
    (index, match, content) = tn.expect(remaining_strings, actual_timeout)
    total_content += content
    if index < 0:
        break
    del remaining_strings[index]

#1