Java字符串。分割-由多个字符分隔符[重复]

This question already has an answer here:

这个问题已经有了答案:

I would like to parse entire file based on all the possible delimiters like commas, colon, semi colons, periods, spaces, hiphens etcs.

我希望基于所有可能的分隔符(如逗号、冒号、半冒号、句点、空格、hiphens etcs)解析整个文件。

Suppose I have a hypothetical string line "Hi,X How-how are:any you?" I should get output array with items Hi,X,How,how,are,any and you.

假设我有一个假设的字符串“Hi,X how - are:any you?”我应该得到输出数组的项Hi,X,How, How, are,any和you。

How do I specify all these delimiter in String.split method?

如何在字符串中指定所有这些分隔符。分割方法?

Thanks in advance.

提前谢谢。

1 个解决方案

String.split takes a regular expression, in this case, you want non-word characters (regex \W) to be the split, so it's simply:

字符串。split取一个正则表达式，在本例中，您希望非单词字符(regex \W)为split，因此它很简单:

String input = "Hi,X How-how are:any you?";
String[] parts = input.split("[\\W]");

If you wanted to be more explicit, you could use the exact characters in the expression:

如果你想要更明确，可以使用表达式中的确切字符:

String[] parts = input.split("[,\\s\\-:\\?]");

String.split takes a regular expression, in this case, you want non-word characters (regex \W) to be the split, so it's simply:

字符串。split取一个正则表达式，在本例中，您希望非单词字符(regex \W)为split，因此它很简单:

String input = "Hi,X How-how are:any you?";
String[] parts = input.split("[\\W]");

If you wanted to be more explicit, you could use the exact characters in the expression:

如果你想要更明确，可以使用表达式中的确切字符:

String[] parts = input.split("[,\\s\\-:\\?]");