通过字符串分隔符将字符串数组分隔为字符串数组

I currently have an array being created like this

我目前有一个像这样创建的数组

let stringSeparator1 = "some string"

if let contentArray = dataString?.components(separatedBy: stringSeparator1) {

    if contentArray.count > 1 {

        //Separate contentArray into array of relevant results
        let stringSeparator2 = "</p>"

        let result = contentArray[1].components(separatedBy: stringSeparator2)

This works great for 1 index position of contentArray. But what I really want to do is go through contentArray from index 1 to contentArray.count and delimit all of the data by stringSeparator2. I've tried several methods using loops and can't find a way that gives me what I need.

这适用于contentArray的1个索引位置。但我真正想做的是从index1到contentArray.count的contentArray，并通过stringSeparator2分隔所有数据。我已经尝试了几种使用循环的方法，但找不到能够满足我需要的方法。

1 个解决方案

#1

Use .map to get array of arrays and .flatMap to get array of strings. You can use various filtering methods (e.g. .filter, .dropFirst, .dropLast, .dropWhile, etc)

使用.map获取数组数组和.flatMap获取字符串数组。您可以使用各种过滤方法（例如.filter，.dropFirst，.dropLast，.dropWhile等）

let dataString: String? = "0-1-2,3-4-5,6-7-8"

// map will result in array of arrays of strings. dropFirst will skip first part (see dropLast, etc)
let mapResult = dataString?.components(separatedBy: ",").dropFirst().map { $0.components(separatedBy: "-") }
print(mapResult) // Optional([["3", "4", "5"], ["6", "7", "8"]])

// flatMap will result in array of strings. dropFirst will skip first part (see dropLast, etc)
let flatMapResult = dataString?.components(separatedBy: ",").dropFirst().flatMap { $0.components(separatedBy: "-") }
print(flatMapResult) // Optional(["3", "4", "5", "6", "7", "8"])