I would like to replace forward slaches to backslashes in emacs lisp. If I use this :
我想在emacs lisp中将前向slaches替换为反斜杠。如果我用这个：
(replace-regexp-in-string "\/" "\\" path))
I get an error.
我收到一个错误。
(error "Invalid use of `\\' in replacement text")
So how to represent the backslash in the second regexp?
那么如何在第二个正则表达式中表示反斜杠？
4 个解决方案
#1
12
What you are seeing in "C:\\foo\\bar" is the textual representation of the string "C:\foo\bar", with escaped backslashes for further processing.
你在“C：\\ foo \\ bar”中看到的是字符串“C：\ foo \ bar”的文本表示，带有用于进一步处理的转义反斜杠。
For example, if you make a string of length 1 with the backslash character:
例如，如果使用反斜杠字符创建长度为1的字符串：
(make-string 1 ?\\)
you get the following response (e.g. in the minibuffer, when you evaluate the above with C-x C-e):
您得到以下响应（例如，在使用C-x C-e评估上述内容时，在迷你缓冲区中）：
"\\"
Another way to get what you want is to switch the "literal" flag on:
获得所需内容的另一种方法是切换“文字”标志：
(replace-regexp-in-string "/" "\\" path t t)
By the way, you don't need to escape the slash.
顺便说一句，你不需要逃避斜线。
#2
6
Does it need to be double-escaped?
是否需要双重转义？
i.e.
即
(replace-regexp-in-string "\/" "\\\\" path)
#3
2
Try using the regexp-quote function, like so:
尝试使用regexp-quote函数，如下所示：
(replace-regexp-in-string "/" (regexp-quote "\\") "this/is//a/test")
（replace-regexp-in-string“/”（regexp-quote“\\”）“this / is // a / test”）
regexp-quote's documentation reads
regexp-quote的文档内容如下
(regexp-quote string) Return a regexp string which matches exactly string and nothing else.
（regexp-quote string）返回一个与字符串完全匹配的regexp字符串。
#4
0
Don't use emacs but I guess it supports some form of specifying unicode via \x
不要使用emacs，但我想它支持通过\ x指定unicode的某种形式
e.g. maybe this works
例如也许这有效
(replace-regexp-in-string "\x005c" "\x005f" path))
or
要么
(replace-regexp-in-string "\u005c" "\u005f" path))
#1
12
What you are seeing in "C:\\foo\\bar" is the textual representation of the string "C:\foo\bar", with escaped backslashes for further processing.
你在“C：\\ foo \\ bar”中看到的是字符串“C：\ foo \ bar”的文本表示，带有用于进一步处理的转义反斜杠。
For example, if you make a string of length 1 with the backslash character:
例如，如果使用反斜杠字符创建长度为1的字符串：
(make-string 1 ?\\)
you get the following response (e.g. in the minibuffer, when you evaluate the above with C-x C-e):
您得到以下响应（例如，在使用C-x C-e评估上述内容时，在迷你缓冲区中）：
"\\"
Another way to get what you want is to switch the "literal" flag on:
获得所需内容的另一种方法是切换“文字”标志：
(replace-regexp-in-string "/" "\\" path t t)
By the way, you don't need to escape the slash.
顺便说一句，你不需要逃避斜线。
#2
6
Does it need to be double-escaped?
是否需要双重转义？
i.e.
即
(replace-regexp-in-string "\/" "\\\\" path)
#3
2
Try using the regexp-quote function, like so:
尝试使用regexp-quote函数，如下所示：
(replace-regexp-in-string "/" (regexp-quote "\\") "this/is//a/test")
（replace-regexp-in-string“/”（regexp-quote“\\”）“this / is // a / test”）
regexp-quote's documentation reads
regexp-quote的文档内容如下
(regexp-quote string) Return a regexp string which matches exactly string and nothing else.
（regexp-quote string）返回一个与字符串完全匹配的regexp字符串。
#4
0
Don't use emacs but I guess it supports some form of specifying unicode via \x
不要使用emacs，但我想它支持通过\ x指定unicode的某种形式
e.g. maybe this works
例如也许这有效
(replace-regexp-in-string "\x005c" "\x005f" path))
or
要么
(replace-regexp-in-string "\u005c" "\u005f" path))