I need all possible combinations of 0,1 of length k.
我需要所有可能的长度为k的组合。
Suppose k=2 I want (0,0), (0,1), (1,0), (1,1)
假设k=2 (0,0) (0,1) (1,0) (1,1)
I have tried different function in itertools but I did not find what I want.
我在itertools中尝试了不同的函数，但是没有找到我想要的。
>>> list(itertools.combinations_with_replacement([0,1], 2))
[(0, 0), (0, 1), (1, 1)]
>>> list(itertools.product([0,1], [0,1])) #does not work if k>2
[(0, 0), (0, 1), (1, 0), (1, 1)]
1 个解决方案
#1
15
itertools.product() takes a repeat keyword argument; set it to k:
product()接受repeat关键字参数;将其设置为凯西:
product(range(2), repeat=k)
Demo:
演示:
>>> from itertools import product
>>> for k in range(2, 5):
... print list(product(range(2), repeat=k))
...
[(0, 0), (0, 1), (1, 0), (1, 1)]
[(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]
[(0, 0, 0, 0), (0, 0, 0, 1), (0, 0, 1, 0), (0, 0, 1, 1), (0, 1, 0, 0), (0, 1, 0, 1), (0, 1, 1, 0), (0, 1, 1, 1), (1, 0, 0, 0), (1, 0, 0, 1), (1, 0, 1, 0), (1, 0, 1, 1), (1, 1, 0, 0), (1, 1, 0, 1), (1, 1, 1, 0), (1, 1, 1, 1)]
#1
15
itertools.product() takes a repeat keyword argument; set it to k:
product()接受repeat关键字参数;将其设置为凯西:
product(range(2), repeat=k)
Demo:
演示:
>>> from itertools import product
>>> for k in range(2, 5):
... print list(product(range(2), repeat=k))
...
[(0, 0), (0, 1), (1, 0), (1, 1)]
[(0, 0, 0), (0, 0, 1), (0, 1, 0), (0, 1, 1), (1, 0, 0), (1, 0, 1), (1, 1, 0), (1, 1, 1)]
[(0, 0, 0, 0), (0, 0, 0, 1), (0, 0, 1, 0), (0, 0, 1, 1), (0, 1, 0, 0), (0, 1, 0, 1), (0, 1, 1, 0), (0, 1, 1, 1), (1, 0, 0, 0), (1, 0, 0, 1), (1, 0, 1, 0), (1, 0, 1, 1), (1, 1, 0, 0), (1, 1, 0, 1), (1, 1, 1, 0), (1, 1, 1, 1)]