遍历xml文件结构并存储它们以供以后在java中的hashmaps中使用

I've XML file structure for single table node as below

我有单表节点的XML文件结构,如下所示

<table ID="123" Name="Prj">
  <select>
        <slno>prjslno</slno>
        <to>prjrecepient</to>
        <from>prjsender</from>
        <body>prjcontent</body>
  </select>
  <where>status="new"</where>
  <successupdate>
        <status>'mail sent'</status>
  </successupdate>
  <failureupdate>
        <status>'mail sending failed'</status>
  </failureupdate>
</table>

There are 3 such nodes in my xml file. I need to traverse the xml file and store the content in hashmap.I've tried to store them in the following format

我的xml文件中有3个这样的节点。我需要遍历xml文件并将内容存储在hashmap中。我试图以下列格式存储它们

key     value
slno    prjslno
to      prjrecepient
from    prjsender
body    prjcontent
where   status="new"

But when I tried to store the status and its value for success and failure updates its getting overwritten and storing 'mail sending failed' value but not 'mail sent'.( I know the reason as the hashmap supports unique key so its storing in this way).

但是当我试图存储状态及其成功和失败的值时,它会被覆盖并存储“邮件发送失败”值而不是“邮件发送”。(我知道原因,因为hashmap支持唯一键,因此它存储在此办法)。

But I need to store them in hashmap for the later use. Is there any way to sort out? please suggest something.

但我需要将它们存储在hashmap*以后使用。有什么方法可以理清吗?请提出建议。

1 个解决方案

#1

I'd create composite keys from the current and it's parent element name, like:

我将从当前及其父元素名称创建复合键,如:

 map.put("succesupdate/status", "'mail sent'");
 map.put("failureupdate/status", "'mail sending failed'");

It will not work in general but could be a solution for your current problem.

它一般不起作用,但可以解决您当前的问题。

#1