来自X-Y坐标的Map的Java字符串

时间:2021-03-18 21:16:40

I have a Map where Coords is defined as so:

我有一个地图,Coords定义如下:

class Coords {
        int x;
        int y;
        public boolean equals(Object o) {
            Coords c = (Coords)o;
            return c.x==x && c.y==y;
        }
        public Coords(int x, int y) {
            super();
            this.x = x;
            this.y = y;
        }
        public int hashCode() {
            return new Integer(x+"0"+y);
        }
    }

(not very good, I know, please don't tease me.) How can I now create a String where the characters are mapped from this map, for example:

(不是很好,我知道,请不要取笑我。)我现在如何创建一个字符串,从这个地图映射字符,例如:

Map<Coords, Character> map = new HashMap<Coords, Character>();
map.put(new Coords(0,0),'H');
map.put(new Coords(1,0),'e');
map.put(new Coords(2,0),'l');
map.put(new Coords(3,0),'l');
map.put(new Coords(4,0),'o');
map.put(new Coords(6,0),'!');
map put(new Coords(6,1),'!');
somehowTransformToString(map); //Hello !
                               //      !

Thanks,
Isaac Waller
(note - it's not homework)

谢谢,艾萨克沃勒(注意 - 这不是作业)

2 个解决方案

#1


  1. Create a comparator which can sort Coords by y and then x:

    创建一个比较器,可以按y然后x对Coords进行排序:

    int d = c1.y - c2.y;
    if (d == 0) d = c1.x - c2.y;
    return d;
    
  2. Create a sorted map:

    创建有序地图:

    TreeMap<Coords, Character> sortedMap = new TreeMap(comparator);
    sortedMap.putAll(map); // copy values from other map
    
  3. Print the values of the map in order:

    按顺序打印地图的值:

    for (Character c: map.values()) System.out.print(c);
    
  4. If you need newlines:

    如果您需要换行:

    int y = -1;
    for (Map.Entry<Coords, Character> e: map.entrySet()) {
        if (e.y != y) {
            if (y != -1) System.out.println();
            y = e.y;
        }
        System.out.print(c);
    }
    

#2


I suggest you add a toString method to Coord or use the Point class.

我建议你向Coord添加一个toString方法或使用Point类。

Map<Point, Character> map = new HashMap<Point , Character>();
map.put(new Point(0,0),'H');
map.put(new Point(1,0),'e');
map.put(new Point(2,0),'l');
map.put(new Point(3,0),'l');
map.put(new Point(4,0),'o');
map.put(new Point(6,0),'!');
map put(new Point(6,1),'!');
String text = map.toString();

If you want to layout the characters you could use multi dimensional array.

如果要布局字符,可以使用多维数组。

char[][] grid = new char[7][2];
grid[0][0] ='H';
grid[0][1] ='e';
grid[0][2] ='l';
grid[0][3] ='l';
grid[0][4] ='o';
grid[0][6] ='!';
grid[1][6] ='!';
for(char[] line: grid) System.out.println(new String(line));

#1


  1. Create a comparator which can sort Coords by y and then x:

    创建一个比较器,可以按y然后x对Coords进行排序:

    int d = c1.y - c2.y;
    if (d == 0) d = c1.x - c2.y;
    return d;
    
  2. Create a sorted map:

    创建有序地图:

    TreeMap<Coords, Character> sortedMap = new TreeMap(comparator);
    sortedMap.putAll(map); // copy values from other map
    
  3. Print the values of the map in order:

    按顺序打印地图的值:

    for (Character c: map.values()) System.out.print(c);
    
  4. If you need newlines:

    如果您需要换行:

    int y = -1;
    for (Map.Entry<Coords, Character> e: map.entrySet()) {
        if (e.y != y) {
            if (y != -1) System.out.println();
            y = e.y;
        }
        System.out.print(c);
    }
    

#2


I suggest you add a toString method to Coord or use the Point class.

我建议你向Coord添加一个toString方法或使用Point类。

Map<Point, Character> map = new HashMap<Point , Character>();
map.put(new Point(0,0),'H');
map.put(new Point(1,0),'e');
map.put(new Point(2,0),'l');
map.put(new Point(3,0),'l');
map.put(new Point(4,0),'o');
map.put(new Point(6,0),'!');
map put(new Point(6,1),'!');
String text = map.toString();

If you want to layout the characters you could use multi dimensional array.

如果要布局字符,可以使用多维数组。

char[][] grid = new char[7][2];
grid[0][0] ='H';
grid[0][1] ='e';
grid[0][2] ='l';
grid[0][3] ='l';
grid[0][4] ='o';
grid[0][6] ='!';
grid[1][6] ='!';
for(char[] line: grid) System.out.println(new String(line));