从字符串中删除特定字符的方法？

I need to remove the brackets "[" and "]" from $widget_text in the variable value below and store the result in $widget_id.

我需要从下面变量值的$ widget_text中删除括号“[”和“]”,并将结果存储在$ widget_id中。

$widget_text = '[widget_and-some-text]';
$widget_id = ?;

Use preg_replace, str_replace or something else?

使用preg_replace,str_replace还是别的什么?

3 个解决方案

#1

There are several methods available, and they can sometimes be made to perform exactly the same task, like preg_replace/str_replace. But, perhaps you want to remove brackets only from the beginning or end of the string; in which case preg_replace works. But, if there could be several brackets, preg_replace can do the job too. But trim is easier and makes more sense.

有几种方法可用,有时可以使它们执行完全相同的任务,例如preg_replace / str_replace。但是,也许你只想从字符串的开头或结尾删除括号;在这种情况下preg_replace工作。但是,如果可以有多个括号,preg_replace也可以完成这项工作。但修剪更容易,更有意义。

preg_replace() - removes beginning and trailing brackets

preg_replace() - 删除开始和结尾括号

$widget_id = preg_replace(array('/^\[/','/\]$/'), '',$widget_text);

str_replace() - this removes brackets anywhere in the text

str_replace() - 这将删除文本中任何位置的括号

$widget_id = str_replace(array('[',']'), '',$widget_text);

trim() - trims brackets from beginning and end

trim() - 从开头和结尾修剪括号

$widget_id = trim($widget_text,'[]')

substr() - does the same as trim() (assuming the widget text does not include any closing brackets within the text)

substr() - 与trim()相同(假设窗口小部件文本不包含文本中的任何右括号)

$widget_id = substr($widget_text,
                    $start = strspn($widget_text, '['),
                    strcspn($widget_text, ']') - $start
             );

#2

$widget_id = str_replace('[', '', str_replace(']', '', $widget_text));

#3

If the brackets are always at first and last position, use this:

如果括号始终位于第一个和最后一个位置,请使用:

$widget_id = substr($widget_text, 1, strlen($widget_text)-2);

I think this is a faster way...

我认为这是一种更快的方式......

#1