DRF框架获取参数的方式

时间:2022-01-05 20:07:03

DRF获取参数的方式


例如url

url(r'^demo/(?P<word>.*)/$', DemoView.as_view())

在类视图中获取参数

url:http://127.0.0.1:8000/demo/aaa/?bbb=bbb&ccc=ccc&ccc=CCC

form:{"body":"body"}

JSON:{"body":"body"}

class DemoView(APIView):

	def post(self, request, aaa):
aaa = aaa # 获取url路径中的参数
bbb_str = request.query_params.get('bbb') # 获取一个查询字符串的参数
ccc_list = request.query_params.getlist('ccc') # 获取多个查询字符串参数
# 请求体中的参数
# 如果通过form表单传递,获取出来是QueryDict,通过.dict()转换成python的字典
form_body = request.data
# 如果通过JSON传递,获取出来就是字典,例如{'body':'body'}
# json_body = request.data
print(aaa)
print(bbb_str)
print(ccc_list)
print(form_body.dict())
# print(json_body)
return Response({'message': 'OK'})

结果

aaa
bbb
['ccc', 'CCC']
{'body': 'body'}

URL路径参数/查询字符串不区分请求方式,GET/POST/PUT等都一样

serializer中获取参数

# view
class DemoView(GenericAPIView):
serializer_class = DemoSerializer def post(self, request, aaa):
serializer = self.get_serializer(data=request.query_params)
serializer.is_valid(raise_exception=True)
return Response({'message': 'OK'}) # serializer
class DemoSerializer(serializers.Serializer):
bbb = serializers.CharField()
ccc = serializers.ListField() # List def validate(self, attrs):
aaa = self.context['view'].kwargs.get('aaa') # 获取路径参数
bbb = attrs['bbb'] # 获取查询字符串
ccc = attrs['ccc'] # 获取以多个key相同的查询字符串
# 获取当前登陆的对象,需要根据场景进行使用
# user = self.context['request'].user
print(aaa)
print(bbb)
print(ccc)
return attrs