PAT L3-007 天梯地图

时间:2022-04-05 15:03:14

https://pintia.cn/problem-sets/994805046380707840/problems/994805051153825792

本题要求你实现一个天梯赛专属在线地图,队员输入自己学校所在地和赛场地点后,该地图应该推荐两条路线:一条是最快到达路线;一条是最短距离的路线。题目保证对任意的查询请求,地图上都至少存在一条可达路线。

输入格式:

输入在第一行给出两个正整数N(2 ≤ N ≤ 500)和M,分别为地图中所有标记地点的个数和连接地点的道路条数。随后M行,每行按如下格式给出一条道路的信息:

V1 V2 one-way length time

其中V1V2是道路的两个端点的编号(从0到N-1);如果该道路是从V1V2的单行线,则one-way为1,否则为0;length是道路的长度;time是通过该路所需要的时间。最后给出一对起点和终点的编号。

输出格式:

首先按下列格式输出最快到达的时间T和用节点编号表示的路线:

Time = T: 起点 => 节点1 => ... => 终点

然后在下一行按下列格式输出最短距离D和用节点编号表示的路线:

Distance = D: 起点 => 节点1 => ... => 终点

如果最快到达路线不唯一,则输出几条最快路线中最短的那条,题目保证这条路线是唯一的。而如果最短距离的路线不唯一,则输出途径节点数最少的那条,题目保证这条路线是唯一的。

如果这两条路线是完全一样的,则按下列格式输出:

Time = T; Distance = D: 起点 => 节点1 => ... => 终点

输入样例1:

10 15
0 1 0 1 1
8 0 0 1 1
4 8 1 1 1
5 4 0 2 3
5 9 1 1 4
0 6 0 1 1
7 3 1 1 2
8 3 1 1 2
2 5 0 2 2
2 1 1 1 1
1 5 0 1 3
1 4 0 1 1
9 7 1 1 3
3 1 0 2 5
6 3 1 2 1
5 3

输出样例1:

Time = 6: 5 => 4 => 8 => 3
Distance = 3: 5 => 1 => 3

输入样例2:

7 9
0 4 1 1 1
1 6 1 3 1
2 6 1 1 1
2 5 1 2 2
3 0 0 1 1
3 1 1 3 1
3 2 1 2 1
4 5 0 2 2
6 5 1 2 1
3 5

输出样例2:

Time = 3; Distance = 4: 3 => 2 => 5

代码:

ACACAC

#include <bits/stdc++.h>
using namespace std; const int inf = 0x3f3f3f3f;
int N, M, st, en;
int mp[][], tim[][];
int vis[], see[], pre[], num[];
int dis[];
int coos[], nx[];
vector<int> v[];
int ans1, ans2; void dijkstra(int act) {
dis[act] = ;
pre[act] = -;
num[act] = ; int temp = act;
for(int i = ; i < N; i ++) {
int minn = inf;
for(int j = ; j < N; j ++) {
if(vis[j]) continue;
if(dis[j] < minn || (dis[j] == minn && num[j] > num[temp])) {
temp = j;
minn = dis[j];
}
} vis[temp] = ;
for(int k = ; k < N; k ++) {
if(vis[k]) continue;
if(dis[k] > dis[temp] + mp[temp][k]) {
dis[k] = dis[temp] + mp[temp][k];
num[k] = num[temp] + ;
pre[k] = temp;
} else if(dis[k] == dis[temp] + mp[temp][k] && num[k] > num[temp] + ) {
num[k] = num[temp] + ;
pre[k] = temp;
}
} } ans1 = dis[en];
} void Dijkstra(int act) {
coos[act] = ;
nx[act] = -; int temp = act; for(int i = ; i < N; i ++) {
int minn = inf;
for(int j = ; j < N; j ++) {
if(see[j]) continue;
if(coos[j] < minn || (coos[j] == minn && dis[j] > dis[temp])) {
temp = j;
minn = coos[j];
}
} see[temp] = ;
for(int k = ; k < N; k ++) {
if(see[k]) continue;
if(coos[k] > coos[temp] + tim[temp][k]) {
coos[k] = coos[temp] + tim[temp][k];
dis[k] = dis[temp] + mp[temp][k];
nx[k] = temp;
} else if(coos[k] == coos[temp] + tim[temp][k] && dis[k] > dis[temp] + mp[temp][k]) {
dis[k] = dis[temp] + mp[temp][k];
nx[k] = temp;
}
}
} ans2 = coos[en]; } int main() {
memset(vis, , sizeof(vis));
memset(see, , sizeof(see));
memset(dis, inf, sizeof(dis));
memset(mp, inf, sizeof(mp));
memset(tim, inf, sizeof(tim));
memset(coos, inf, sizeof(coos));
scanf("%d%d", &N, &M);
for(int i = ; i < M; i ++) {
int uu, vv, dir, len, t;
scanf("%d%d%d%d%d", &uu, &vv, &dir, &len, &t);
if(dir == ) {
v[uu].push_back(vv);
v[vv].push_back(uu);
mp[uu][vv] = mp[vv][uu] = len;
tim[uu][vv] = tim[vv][uu] = t;
} else {
v[uu].push_back(vv);
mp[uu][vv] = len;
tim[uu][vv] = t;
}
}
scanf("%d%d", &st, &en); string s1 = "", s2 = "";
dijkstra(st);
Dijkstra(st); stack<int> s3, s4; bool same = true;
int n1 = en, n2 = en;
vector<int> v1, v2; while(n1 != -) {
v1.push_back(n1);
n1 = pre[n1];
}
while(n2 != -) {
v2.push_back(n2);
n2 = nx[n2];
} if(v1.size() != v2.size()) same = false;
else {
int m = v1.size();
for(int i = ; i < m; i ++) {
if(v1[i] != v2[i]) {
same = false;
break;
}
}
} int mintime = ans2;
int minway = ans1; if(!same) { printf("Time = %d: ", mintime);
stack<int> s2;
int lastt = en;
while(lastt != -) {
s2.push(lastt);
lastt = nx[lastt];
}
printf("%d", s2.top());
s2.pop();
while(!s2.empty()) {
printf(" => %d", s2.top());
s2.pop();
} printf("\n"); printf("Distance = %d: ", minway);
stack<int> s1;
int last = en;
while(last != -) {
s1.push(last);
last = pre[last];
}
printf("%d", s1.top());
s1.pop();
while(!s1.empty()) {
printf(" => %d", s1.top());
s1.pop();
}
} else {
printf("Time = %d; Distance = %d: ", mintime, minway);
stack<int> s1;
int last = en;
while(last != -) {
s1.push(last);
last = pre[last];
}
printf("%d", s1.top());
s1.pop();
while(!s1.empty()) {
printf(" => %d", s1.top());
s1.pop();
}
} return ;
}

WA 掉的 

#include <bits/stdc++.h>
using namespace std; const int inf = 0x3f3f3f3f;
int N, M, st, en;
int mp[550][550], tim[550][550];
int vis[550], see[550], pre[550], num[550];
int dis[550];
int coos[550], nx[550];
vector<int> v[550]; void dijkstra(int act) {
dis[act] = 0;
pre[act] = -1;
num[act] = 1; int temp = act;
for(int i = 0; i < N; i ++) {
int minn = inf;
for(int j = 0; j < N; j ++) {
if(vis[j]) continue;
if(dis[j] < minn || (dis[j] == minn && num[j] > num[temp] + 1)) {
temp = j;
minn = dis[j];
}
} vis[temp] = 1;
for(int k = 0; k < N; k ++) {
if(vis[k]) continue;
if(dis[k] > dis[temp] + mp[temp][k]) {
dis[k] = dis[temp] + mp[temp][k];
num[k] = num[temp] + 1;
pre[k] = temp;
} else if(dis[k] == dis[temp] + mp[temp][k] && num[k] > num[temp] + 1) {
num[k] = num[temp] + 1;
pre[k] = temp;
}
} }
} void Dijkstra(int act) {
coos[act] = 0;
nx[act] = -1; int temp = act; for(int i = 0; i < N; i ++) {
int minn = inf;
for(int j = 0; j < N; j ++) {
if(see[j]) continue;
if(coos[j] < minn || (coos[j] == minn && dis[j] > dis[temp] + mp[temp][j])) {
temp = j;
minn = coos[j];
}
} see[temp] = 1;
for(int k = 0; k < N; k ++) {
if(see[k]) continue;
if(coos[k] > coos[temp] + tim[temp][k]) {
coos[k] = coos[temp] + tim[temp][k];
nx[k] = temp;
} else if(coos[k] == coos[temp] + tim[temp][k] && dis[k] > dis[temp] + mp[temp][k]) {
nx[k] = temp;
}
}
}
} int main() {
memset(vis, 0, sizeof(vis));
memset(see, 0, sizeof(see));
memset(dis, inf, sizeof(dis));
memset(mp, inf, sizeof(mp));
memset(tim, inf, sizeof(tim));
memset(coos, inf, sizeof(coos));
scanf("%d%d", &N, &M);
for(int i = 0; i < M; i ++) {
int uu, vv, dir, len, t;
scanf("%d%d%d%d%d", &uu, &vv, &dir, &len, &t);
if(dir == 0) {
v[uu].push_back(vv);
v[vv].push_back(uu);
mp[uu][vv] = mp[vv][uu] = len;
tim[uu][vv] = tim[vv][uu] = t;
} else {
v[uu].push_back(vv);
mp[uu][vv] = len;
tim[uu][vv] = t;
}
}
scanf("%d%d", &st, &en); string s1 = "", s2 = "";
dijkstra(st);
Dijkstra(st); stack<int> s3, s4; bool same = false;
int n1 = en, n2 = en;
vector<int> v1, v2; while(n1 != -1) {
v1.push_back(n1);
n1 = pre[n1];
}
while(n2 != -1) {
v2.push_back(n2);
n2 = nx[n2];
} if(v1.size() != v2.size()) same = false;
else {
int m = v1.size();
for(int i = 0; i < m; i ++) {
if(v1[i] == v2[i]) {
same = true;
break;
}
}
} int mintime = coos[en];
int minway = dis[en]; if(!same) { printf("Time = %d: ", mintime);
stack<int> s2;
int lastt = en;
while(lastt != -1) {
s2.push(lastt);
lastt = nx[lastt];
}
printf("%d", s2.top());
s2.pop();
while(!s2.empty()) {
printf(" => %d", s2.top());
s2.pop();
} printf("\n"); printf("Distance = %d: ", minway);
stack<int> s1;
int last = en;
while(last != -1) {
s1.push(last);
last = pre[last];
}
printf("%d", s1.top());
s1.pop();
while(!s1.empty()) {
printf(" => %d", s1.top());
s1.pop();
}
} else {
printf("Time = %d; Distance = %d: ", mintime, minway);
stack<int> s1;
int last = en;
while(last != -1) {
s1.push(last);
last = pre[last];
}
printf("%d", s1.top());
s1.pop();
while(!s1.empty()) {
printf(" => %d", s1.top());
s1.pop();
}
} return 0;
}

  差两个测试点没过 但是实在是写的头大 如果有旁友知道我错的点请私信我!谢谢!!!!

PAT L3-007 天梯地图