With sed, what is a one liner to print the first n characters. I am doing the following.
使用sed,打印前n个字符的单个衬垫是什么。我正在做以下事情。
grep -G 'defn -test.*' OctaneFullTest.clj | sed ....
5 个解决方案
#1
Don't use sed, use cut.
不要使用sed,使用切割。
grep .... | cut -c 1-N
If you MUST use sed:
如果你必须使用sed:
grep ... | sed -e 's/^\(.\{12\}\).*/\1/'
#2
colrm x
For example, if you need the first 100 characters:
例如,如果您需要前100个字符:
cat file |colrm 101
It's been around for years and is in most linux's and bsd's (freebsd for sure), usually by default. I can't remember ever having to type apt-get install colrm.
它已存在多年,并且通常默认情况下是大多数linux和bsd(肯定是freebsd)。我不记得曾经输入过apt-get install colrm。
#3
don't have to use grep either
也不必使用grep
an example:
sed -n '/searchwords/{s/^\(.\{12\}\).*/\1/g;p}' file
#4
Strictly with sed:
严格用sed:
grep ... | sed -e 's/^\(.\{N\}\).*$/\1/'
#5
To print the N first characters you can remove the N+1 characters up to the end of line:
要打印N个第一个字符,您可以删除N + 1个字符,直到行尾:
$ sed 's/.//5g' <<< "defn-test"
defn
#1
Don't use sed, use cut.
不要使用sed,使用切割。
grep .... | cut -c 1-N
If you MUST use sed:
如果你必须使用sed:
grep ... | sed -e 's/^\(.\{12\}\).*/\1/'
#2
colrm x
For example, if you need the first 100 characters:
例如,如果您需要前100个字符:
cat file |colrm 101
It's been around for years and is in most linux's and bsd's (freebsd for sure), usually by default. I can't remember ever having to type apt-get install colrm.
它已存在多年,并且通常默认情况下是大多数linux和bsd(肯定是freebsd)。我不记得曾经输入过apt-get install colrm。
#3
don't have to use grep either
也不必使用grep
an example:
sed -n '/searchwords/{s/^\(.\{12\}\).*/\1/g;p}' file
#4
Strictly with sed:
严格用sed:
grep ... | sed -e 's/^\(.\{N\}\).*$/\1/'
#5
To print the N first characters you can remove the N+1 characters up to the end of line:
要打印N个第一个字符,您可以删除N + 1个字符,直到行尾:
$ sed 's/.//5g' <<< "defn-test"
defn