leetcode 6. ZigZag Conversion [java]

时间:2022-02-14 07:58:49

自己写的:

if(numRows == 1)   return s;
int ll = s.length() / 2 + 1;
Character tc[] = new Character[numRows* ll];
int i = 0, j = 0;
boolean down = true;
for(int k = 0; k < s.length(); k++){
tc[i* ll + j] = s.charAt(k);
if(down){
i++;
if(i == numRows){
i -= 2;
j ++;
down = false;
}
}else{
i--;
j++;
if(i == -1){
i = 1;
j --;
down = true;
}
}
}
String res = "";
for(i=0;i < tc.length; i ++){
if(tc[i] != null)
res += tc[i];
}
return res;

参考于discuss:

char[] c = s.toCharArray();
int len = c.length;
StringBuffer[] sb = new StringBuffer[numRows];
for (int i = 0; i < sb.length; i++) sb[i] = new StringBuffer(); int i = 0;
while(i < len){
for (int idx = 0; idx < numRows&&i < len; idx ++)
sb[idx].append(c[i++]);
for (int idx = numRows -2; idx >= 1 && i < len; idx --)
sb[idx].append(c[i++]);
}
for(int idx = 1;idx < sb.length; idx ++)
sb[0].append(sb[idx]);
return sb[0].toString();