C# 模拟提交带附件(input type=file)的表单

时间:2022-03-01 07:48:25

今天调用某API时,对于文档中的传入参数:File[] 类型,感觉很陌生,无从下手! 按通常的方式在json参数中加入file的二进制数据提交,一直报错(参数错误)!后来经过多方咨询,是要换一种

表单提交方式,即:模拟提交带附件的表单!在网上扒出了一个用于提交带附件表单的类!使用方法如下:

使用  参考代码(工具类代码在下面):

                //构造文件
FormUpload.FileParameter file = new FormUpload.FileParameter(File.ReadAllBytes("D://TestAdvertiserFile.jpg"), "TestAdvertiserFile.jpg"); //构造参数
Dictionary<string, object> postParams = new Dictionary<string, object>();
postParams.Add("demoId", );
postParams.Add("token", "TnQqQSDFSDI#2121231");
postParams.Add("advertiserId", input.SinaInput.Id);
postParams.Add("name", input.SinaInput.Name);
postParams.Add("industry",input.SinaInput.Industry); //文件作为参数加入,如果有多个文件,可以参照加入多个
postParams.Add("qualificationFiles", file); //提交请求,获得返回结果
var httpWebResp = FormUpload.MultipartFormDataPost("http://amp.ad.sina.com.cn/sax/interface/advertiser/upload.action", "Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.19 (KHTML, like Gecko) Chrome/18.0.1025.3 Safari/535.19", postParams); Stream instream = httpWebResp.GetResponseStream();
StreamReader sr = new StreamReader(instream,Encoding.UTF8);
//返回结果网页(html)代码
string response = sr.ReadToEnd();
sr.Close();

工具类如下:

    // Implements multipart/form-data POST in C# http://www.ietf.org/rfc/rfc2388.txt
// http://www.briangrinstead.com/blog/multipart-form-post-in-c
public static class FormUpload
{
private static readonly Encoding encoding = Encoding.UTF8; public static HttpWebResponse MultipartFormDataPost(string postUrl, string userAgent, Dictionary<string, object> postParameters)
{
string formDataBoundary = String.Format("----------{0:N}", Guid.NewGuid());
string contentType = "multipart/form-data; boundary=" + formDataBoundary; byte[] formData = GetMultipartFormData(postParameters, formDataBoundary); return PostForm(postUrl, userAgent, contentType, formData);
} private static HttpWebResponse PostForm(string postUrl, string userAgent, string contentType, byte[] formData)
{
HttpWebRequest request = WebRequest.Create(postUrl) as HttpWebRequest; if (request == null)
{
throw new NullReferenceException("request is not a http request");
} // Set up the request properties.
request.Method = "POST";
request.ContentType = contentType;
request.UserAgent = userAgent;
request.CookieContainer = new CookieContainer();
request.ContentLength = formData.Length; // You could add authentication here as well if needed:
// request.PreAuthenticate = true;
// request.AuthenticationLevel = System.Net.Security.AuthenticationLevel.MutualAuthRequested;
// request.Headers.Add("Authorization", "Basic " + Convert.ToBase64String(System.Text.Encoding.Default.GetBytes("username" + ":" + "password"))); // Send the form data to the request.
using (Stream requestStream = request.GetRequestStream())
{
requestStream.Write(formData, , formData.Length);
requestStream.Close();
} return request.GetResponse() as HttpWebResponse;
} private static byte[] GetMultipartFormData(Dictionary<string, object> postParameters, string boundary)
{
Stream formDataStream = new System.IO.MemoryStream();
bool needsCLRF = false; foreach (var param in postParameters)
{
// Thanks to feedback from commenters, add a CRLF to allow multiple parameters to be added.
// Skip it on the first parameter, add it to subsequent parameters.
if (needsCLRF)
formDataStream.Write(encoding.GetBytes("\r\n"), , encoding.GetByteCount("\r\n")); needsCLRF = true; if (param.Value is FileParameter)
{
FileParameter fileToUpload = (FileParameter)param.Value; // Add just the first part of this param, since we will write the file data directly to the Stream
string header = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"; filename=\"{2}\";\r\nContent-Type: {3}\r\n\r\n",
boundary,
param.Key,
fileToUpload.FileName ?? param.Key,
fileToUpload.ContentType ?? "application/octet-stream"); formDataStream.Write(encoding.GetBytes(header), , encoding.GetByteCount(header)); // Write the file data directly to the Stream, rather than serializing it to a string.
formDataStream.Write(fileToUpload.File, , fileToUpload.File.Length);
}
else
{
string postData = string.Format("--{0}\r\nContent-Disposition: form-data; name=\"{1}\"\r\n\r\n{2}",
boundary,
param.Key,
param.Value);
formDataStream.Write(encoding.GetBytes(postData), , encoding.GetByteCount(postData));
}
} // Add the end of the request. Start with a newline
string footer = "\r\n--" + boundary + "--\r\n";
formDataStream.Write(encoding.GetBytes(footer), , encoding.GetByteCount(footer)); // Dump the Stream into a byte[]
formDataStream.Position = ;
byte[] formData = new byte[formDataStream.Length];
formDataStream.Read(formData, , formData.Length);
formDataStream.Close(); return formData;
} public class FileParameter
{
public byte[] File { get; set; }
public string FileName { get; set; }
public string ContentType { get; set; }
public FileParameter(byte[] file) : this(file, null) { }
public FileParameter(byte[] file, string filename) : this(file, filename, null) { }
public FileParameter(byte[] file, string filename, string contenttype)
{
File = file;
FileName = filename;
ContentType = contenttype;
}
}
}