如何检查我的哈希是否有来自字符串数组的键?

时间:2022-08-18 07:27:31

With Ruby, if I have a hash, what is the fastest way to check if it has a key from an array of strings? So I could do this

使用Ruby,如果我有一个哈希,检查它是否有来自字符串数组的键的最快方法是什么?所以我能做到这一点

has_key = false
arr_of_strings.each do |str|
    if my_hash.has_key?(str)
        has_key = true
        break
    end
end

But taht seems like way too many lines of code for such a simple inquiry.

但对于如此简单的查询,似乎有太多代码行。

3 个解决方案

#1


1  

strings = ['a', 'b', 'c']
hash = {:a => 'apple', :b => 'bob', :d => 'thing'}

has_key = hash.keys.map(&:to_s) & strings  # ['a', 'b']
has_key.any? # true

a one-liner that's similar, hash.keys.detect { |key| strings.include?(key.to_s) }.nil?

一个类似的单行,hash.keys.detect {| key | strings.include?(key.to_s)} .nil?

#2


5  

As simple as this:

就这么简单:

arr_of_strings.any? {|s| my_hash.key?(s) }

Or, to get bonus points for clever-yet-less-readable code:

或者,为巧妙但不易读的代码获得奖励积分:

arr_of_strings.any?(&my_hash.method(:key?)) # => true

#3


3  

To see if the array and the keys have any in common, you can use set intersection:

要查看数组和键是否有任何共同点,可以使用set intersection:

(arr & hash.keys).any?

#1


1  

strings = ['a', 'b', 'c']
hash = {:a => 'apple', :b => 'bob', :d => 'thing'}

has_key = hash.keys.map(&:to_s) & strings  # ['a', 'b']
has_key.any? # true

a one-liner that's similar, hash.keys.detect { |key| strings.include?(key.to_s) }.nil?

一个类似的单行,hash.keys.detect {| key | strings.include?(key.to_s)} .nil?

#2


5  

As simple as this:

就这么简单:

arr_of_strings.any? {|s| my_hash.key?(s) }

Or, to get bonus points for clever-yet-less-readable code:

或者,为巧妙但不易读的代码获得奖励积分:

arr_of_strings.any?(&my_hash.method(:key?)) # => true

#3


3  

To see if the array and the keys have any in common, you can use set intersection:

要查看数组和键是否有任何共同点,可以使用set intersection:

(arr & hash.keys).any?