如何使用正则表达式获取两个特定字符串之间的字符串？

I have a string like this,

我有一个像这样的字符串,

green open calldetails  1 0 4 0 10.7kb 10.7kb 
green open stocksummary 1 0 3 0  8.6kb  8.6kb

I need to obtain Stocksummary and calldetails from this. This is what i have tried using regex,

我需要从中获取Stocksummary和calldetails。这是我尝试使用正则表达式,

var result = string.match(/(?:open )(.+)(?:1)/)[1];

Here is my full function:

这是我的全部功能:

routerApp.controller("elasticindex",function($scope,es){
  es.cat.indices("b",function(r,q){
   String St = string.match(/(?:open )(.+)(?:1)/)[1];
  console.log(r,q);
});
});

Desired Output:

calldetails
stocksummary 

1 个解决方案

#1

This non-greedy (lazy) regex should work instead:

这个非贪婪(懒惰)正则表达式应该工作:

/open +(.+?) +1/

RegEx Demo

var result = string.match(/open +(.+?) +1/)[1];

Or safe approach:

或安全的方法:

var result = (string.match(/open +(.+?) +1/) || ['', ''])[1];

Code:

var re = /open +(.+?) +1/g,
    matches = [],
    input = "green open calldetails 1 0 4 0 10.7kb 10.7kb green open stocksummary 1 0 3 0 8.6kb 8.6kb";
while (match = re.exec(input)) matches.push(match[1]);
console.log(matches);

JsFiddle Demo