题目大意：输入n组数据，每组数据中又有若干长度不大于100的整数，以0结束每组数据的输入，求每组中数据之和。每两组数据输入之间有一行空格，输出也是如此。
Integer Inquiry
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 17770 Accepted Submission(s):
4628
Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and
he explored taking various sums of those numbers.
``This supercomputer is
great,'' remarked Chip. ``I only wish Timothy were here to see these results.''
(Chip moved to a new apartment, once one became available on the third floor of
the Lemon Sky apartments on Third Street.)
each of which contains a single VeryLongInteger. Each VeryLongInteger will be
100 or fewer characters in length, and will only contain digits (no
VeryLongInteger will be negative).
The final input line will contain a
single zero on a line by itself.
VeryLongIntegers given in the input.
This problem contains multiple
test cases!
The first line of a multiple input is an integer N, then a
blank line followed by N input blocks. Each input block is in the format
indicated in the problem description. There is a blank line between input
blocks.
The output format consists of N output blocks. There is a blank
line between output blocks.
0
import java.math.BigDecimal;
import java.math.BigInteger;
import java.util.Scanner;
public class Main1047 {
public static void main(String[] args) {
Scanner cin=new Scanner(System.in);
while(cin.hasNext()){
int n=cin.nextInt();
Object obj=BigInteger.ZERO;
for(int i=0;i<n;i++){
BigInteger sum=BigInteger.ZERO;
while(true){
BigInteger b=cin.nextBigInteger();
if(b.equals(obj)){//这里也可以用commparTo(BigInteger.ZERO)==0进行判断；
System.out.println(sum);
if(i!=n-1)
System.out.println();
break;
}
sum=sum.add(b);
}
}
}
}
}