return 程序返回，不再执行下面的代码(结束当前的方法 直接返回)
break 跳出总上一层循环，不再执行循环(结束当前的循环体)
continue 跳出本次循环，继续执行下次循环(结束正在执行的循环 进入下一个循环条件)
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- #include <> typedef struct Node { int index; struct Node *next; }JosephuNode; int Josephu(int n, int m) { int i, j; JosephuNode *head, *tail; head = tail = (JosephuNode *)malloc(sizeof(JosephuNode)); for (i = 1; i < n; ++i) { tail->index = i; tail->next = (JosephuNode *)malloc(sizeof(JosephuNode)); tail = tail->next; } tail->index = i; tail->next = head; for (i = 1; tail != head; ++i) { for (j = 1; j < m; ++j) { tail = head; head = head->next; } tail->next = head->next; printf("第%4d个出局的人是：%4d号\n", i, head->index); free(head); head = tail->next; } i = head->index; free(head); return i; } int main { int n, m; scanf("%d%d", &n, &m); printf("最后胜利的是%d号！\n", Josephu(n, m)); system("pause"); return 0; }">设编号为1，2，… n的n个人围坐一圈，约定编号为k（1数组实现： #include <> #include <> int Josephu(int n, int m) { int flag, i, j = 0; int *arr = (int *)malloc(n * sizeof(int)); for (i = 0; i < n; ++i) arr[i] = 1; for (i = 1; i < n; ++i) { flag = 0; while (flag < m) { if (j == n) j = 0; if (arr[j]) ++flag; ++j; } arr[j - 1] = 0; printf("第%4d个出局的人是：%4d号\n", i, j); } free(arr); return j; } int main { int n, m; scanf("%d%d", &n, &m); printf("最后胜利的是%d号！\n", Josephu(n, m)); system("pause"); return 0; } 链表实现： #include <> #include <> typedef struct Node { int index; struct Node *next; }JosephuNode; int Josephu(int n, int m) { int i, j; JosephuNode *head, *tail; head = tail = (JosephuNode *)malloc(sizeof(JosephuNode)); for (i = 1; i < n; ++i) { tail->index = i; tail->next = (JosephuNode *)malloc(sizeof(JosephuNode)); tail = tail->next; } tail->index = i; tail->next = head; for (i = 1; tail != head; ++i) { for (j = 1; j < m; ++j) { tail = head; head = head->next; } tail->next = head->next; printf("第%4d个出局的人是：%4d号\n", i, head->index); free(head); head = tail->next; } i = head->index; free(head); return i; } int main { int n, m; scanf("%d%d", &n, &m); printf("最后胜利的是%d号！\n", Josephu(n, m)); system("pause"); return 0; }