编译原理LL1文法Follow集算法实现

时间:2022-05-20 15:53:28
import hjzgg.first.First;

import java.util.LinkedHashMap;
import java.util.Map;
import java.util.Set;
import java.util.TreeMap;
import java.util.TreeSet; public class Follow {
private Map<String, Set<Character>> first = null;
private Map<String, Set<Character>> follow = new TreeMap<String, Set<Character>>();
private Map<String, String[]> mp = null;
public Follow(Map<String, String[]> mp, Map<String, Set<Character>> first) {
super();
this.first = first;
this.mp = mp;
} public Map<String, Set<Character>> getFollowSet(){
return follow;
} private void getFirstSet(Set<Character> st, String node, int k){
if(k >= node.length()) return;
if(node.charAt(k)=='\'') --k;
String nextNode = "" + node.charAt(k);
if(k+1<node.length() && node.charAt(k+1)=='\''){
nextNode += '\'';
++k;
}
if(!mp.containsKey(nextNode)){//终结点
st.add(nextNode.charAt(0));
} else {
st.addAll(first.get(nextNode));
if(first.get(nextNode).contains('$'))
getFirstSet(st, node, k+1);
}
} private void findFollow(String curNode){
Set<Character> st = null;
for(String leftNode : mp.keySet()){
String rightNodes[] = mp.get(leftNode);
for(int i=0; i<rightNodes.length; ++i){
int index = rightNodes[i].indexOf(curNode, 0);
while(index != -1){
int nextIndex = index + 1;
if(curNode.length()==1 && index+1<rightNodes[i].length() && rightNodes[i].charAt(index+1)=='\''){
index = rightNodes[i].indexOf(curNode, nextIndex);
continue;
}
index = index+curNode.length();
if(index == rightNodes[i].length()){//末尾的非终结点, A->@B
if(follow.get(leftNode) == null)
findFollow(leftNode);
if(follow.get(curNode) == null){
st = new TreeSet<Character>();
st.addAll(follow.get(leftNode));
follow.put(curNode, st);
}
else follow.get(curNode).addAll(follow.get(leftNode));
} else {
String nextNode = ""+rightNodes[i].charAt(index);
if(index+1 < rightNodes[i].length() && rightNodes[i].charAt(index+1)=='\''){
nextNode += '\'';
++index;
}
if(mp.containsKey(nextNode)){//非终结符
if(first.get(nextNode).contains(new Character('$'))){//A->@B&, 而 &->$
if(follow.get(leftNode) == null)
findFollow(leftNode);
if(follow.get(curNode) == null){
st = new TreeSet<Character>();
st.addAll(follow.get(leftNode));
follow.put(curNode, st);
}
else follow.get(curNode).addAll(follow.get(leftNode));
} //好特殊的情况啊....
{//A->@B&, First(&)^$ 放入follow(B)
Set<Character> tmpSt = new TreeSet<Character>();
getFirstSet(tmpSt, rightNodes[i], index);
tmpSt.remove('$');
if(follow.get(curNode) == null){
st = new TreeSet<Character>();
st.addAll(tmpSt);
follow.put(curNode, st);
}
else follow.get(curNode).addAll(tmpSt);
}
} else {//终结符
if(follow.get(curNode) == null){
st = new TreeSet<Character>();
st.add(nextNode.charAt(0));
follow.put(curNode, st);
}
else follow.get(curNode).add(nextNode.charAt(0));
}
}
index = rightNodes[i].indexOf(curNode, nextIndex);
}
}
}
} public String followKernealCode(){
String content = "";
boolean flag = true;
for(String leftNode : mp.keySet()){
if(flag){
Set<Character> st = new TreeSet<Character>();
st.add('#');
follow.put(leftNode, st);
flag = false;
}
findFollow(leftNode);
}
//打印first集合
System.out.println("Follow 集合如下:");
for(Map.Entry<String, Set<Character>> entry : follow.entrySet()){
content += entry.getKey() + " : " + entry.getValue() + "\n";
System.out.println(entry.getKey() + " : " + entry.getValue());
}
return content;
} public static void main(String[] args) {
String[] rightLinearGrammar = {
"E->TE\'",
"E\'->+TE\'|$",
"T->FT\'",
"T\'->*FT\'|$",
"F->(E)|i"
}; // String[] rightLinearGrammar = {
// "S->ABc",
// "A->a|$",
// "B->b|$"
// }; Map<String, String[]> mp = new LinkedHashMap<String, String[]>();
try{
for(int i=0; i<rightLinearGrammar.length; ++i){
String split1[] = rightLinearGrammar[i].split("->");
String split2[] = split1[1].split("\\|");
mp.put(split1[0], split2);
} } catch(Exception e){
e.printStackTrace();
System.out.println("右线性文法错误!");
}
First first = new First(mp);
first.firstKernealCode();
new Follow(mp, first.getFirstSet()).followKernealCode();
} }