迭代器 - 为vector :: iterator和array :: iterator重载函数

时间:2023-01-08 04:20:58

I'm trying to overload a certain function so only iterators of contiguous containers (which are std::vector::iterator ,std::array::iterator ,and built-in arrays iterators == raw pointers) can be a valid argument.

我正在尝试重载某个函数,所以只有连续容器的迭代器(std :: vector :: iterator,std :: array :: iterator和内置数组迭代器==原始指针)才能成为有效参数。

for some reason my functions fail to compile for vector and std::array :

由于某种原因,我的函数无法编译vector和std :: array:

functions:

template <class T,size_t N>
void catchIterator(typename std::array<T, N>::iterator it) {
    //do somthing
}

template <class T>
void catchIterator(typename std::vector<T>::iterator it) {
    //do somthing
}

example of use :

使用示例:

std::array<int, 10> arr;
auto it = arr.begin();
catchIterator(it);

std::vector<int> vec;
auto it0 = vec.begin();
catchIterator(it0);

Errors :

Error (active)      no instance of overloaded function "catchIterator" matches the argument list
Error (active)      no instance of overloaded function "catchIterator" matches the argument list    
Error   C2783   'void catchIterator(std::array<_Ty,_Size>::iterator)': could not deduce template argument for 'T'   

Error   C2783   'void catchIterator(std::array<_Ty,_Size>::iterator)': could not deduce template argument for 'N'

Error   C2672   'catchIterator': no matching overloaded function found  

I'm using VC++ with Visual studio 2015 RTM.

我在Visual Studio 2015 RTM中使用VC ++。

The errors are pretty self-explanatory, but I wonder if the compiler couldn't really deduce T and N from it and it0, after all, it is part of it/it0 type..

错误是非常明显的,但我想知道编译器是否真的不能从它和it0中推断出T和N,毕竟它是它/ it0类型的一部分..

how can make it work?

怎么能让它起作用?

Edit:
I'll go with @ForEveR suggestion and pass the container+iterator/index as arguments instead. thanks!

编辑:我将使用@ForEveR建议并将容器+迭代器/索引作为参数传递。谢谢!

1 个解决方案

#1


4  

Your functions cannot work, since compiler cannot deduce T and N from iterator, that you send to function. You can use std::enable_if.

你的函数不能工作,因为编译器不能从迭代器中推导出你发送给函数的T和N.您可以使用std :: enable_if。

template <class Iterator>
typename std::enable_if<std::is_same<Iterator, typename std::array<typename std::iterator_traits<Iterator>::value_type, 1>::iterator>::value, void>::type
catchIterator(Iterator it) {
    //do somthing
}

template <class Iterator>
typename std::enable_if<std::is_same<Iterator, typename std::vector<typename std::iterator_traits<Iterator>::value_type>::iterator>::value, void>::type 
catchIterator(Iterator it) {
    //do somthing
}

But there is actually a problem if vector::iterator and array::iterator are of the same type (on gcc for example) - code will not compile, since compiler will not know which function it should use.

但是如果vector :: iterator和array :: iterator属于同一类型(例如在gcc上)实际上存在问题 - 代码将无法编译,因为编译器不知道它应该使用哪个函数。

The best way is to just pass container as first argument and iterator as second.

最好的方法是将容器作为第一个参数传递,将迭代器作为第二个参数传递。

template <typename T, size_t N>
void catchIterator(const std::array<T, N> &, typename std::array<T, N>::iterator it) {
    //do somthing
}

template <typename T>
void catchIterator(const std::vector<T> &, typename std::vector<T>::iterator) {
    //do somthing
}

#1


4  

Your functions cannot work, since compiler cannot deduce T and N from iterator, that you send to function. You can use std::enable_if.

你的函数不能工作,因为编译器不能从迭代器中推导出你发送给函数的T和N.您可以使用std :: enable_if。

template <class Iterator>
typename std::enable_if<std::is_same<Iterator, typename std::array<typename std::iterator_traits<Iterator>::value_type, 1>::iterator>::value, void>::type
catchIterator(Iterator it) {
    //do somthing
}

template <class Iterator>
typename std::enable_if<std::is_same<Iterator, typename std::vector<typename std::iterator_traits<Iterator>::value_type>::iterator>::value, void>::type 
catchIterator(Iterator it) {
    //do somthing
}

But there is actually a problem if vector::iterator and array::iterator are of the same type (on gcc for example) - code will not compile, since compiler will not know which function it should use.

但是如果vector :: iterator和array :: iterator属于同一类型(例如在gcc上)实际上存在问题 - 代码将无法编译,因为编译器不知道它应该使用哪个函数。

The best way is to just pass container as first argument and iterator as second.

最好的方法是将容器作为第一个参数传递,将迭代器作为第二个参数传递。

template <typename T, size_t N>
void catchIterator(const std::array<T, N> &, typename std::array<T, N>::iterator it) {
    //do somthing
}

template <typename T>
void catchIterator(const std::vector<T> &, typename std::vector<T>::iterator) {
    //do somthing
}