Codeforces Round #213 (Div. 2) A. Good Number

时间:2021-01-13 02:45:01
#include <iostream>
#include <vector> using namespace std;
int main(){
int n,k,cnt = ;
cin >> n >>k;
for( int i = ; i < n ; ++ i ){
int a;
vector<int> goodNum(k+,);
cin >> a;
while(a){
if(a%<=k) goodNum[a%]++;
a/=;
}
int j = ;
for(j = ; j < k+; ++ j)
if(!goodNum[j]) break;
if(j >= k +) cnt++;
}
cout<<cnt<<endl;
return ;
}