#-*- coding: UTF-8 -*-
#Tags:dynamic programming,sumRange(i,j)=sum(j)-sum(i-1)
class NumArray(object):
sums=[]
def __init__(self, nums):
"""
initialize your data structure here.
:type nums: List[int]
"""
self.nums=nums
self.sums=nums
for i in xrange(1,len(self.sums)):
self.sums[i]+=self.sums[i-1]
def sumRange(self, i, j):
"""
sum of elements nums[i..j], inclusive.
:type i: int
:type j: int
:rtype: int
"""
if i>j or j>=len(self.sums):return 0
return self.sums[j] if i==0 else (self.sums[j]-self.sums[i-1])
numArray = NumArray([-2, 0, 3, -5, 2, -1])
print numArray.sumRange(3,4)
相关文章
- 【刷题-LeetCode】304. Range Sum Query 2D - Immutable
- [LeetCode] 304. Range Sum Query 2D - Immutable 二维区域和检索 - 不可变
- [leetcode]304. Range Sum Query 2D - Immutable二维区间求和 - 不变
- 【LeetCode】304. Range Sum Query 2D - Immutable 解题报告(Python)
- LeetCode(304)Range Sum Query 2D - Immutable
- [LeetCode] Range Sum Query 2D - Immutable 二维区域和检索 - 不可变
- LeetCode() Range Sum Query-mutable
- Java [Leetcode 303]Range Sum Query - Immutable
- [LeetCode] 303. Range Sum Query - Immutable (Easy)
- 303. Range Sum Query - Immutable