Was hoping someone can help out with this. I am trying to figure out how to display the first line that contains a certain string i.e. "computer" (first occurrence of "computer" in a txt file). I would prefer to do this using grep.
希望有人可以帮忙解决这个问题。我试图弄清楚如何显示包含某个字符串的第一行，即“计算机”（txt文件中第一次出现“计算机”）。我更喜欢用grep这样做。
I know grep "computer" somefile.txt
我知道grep“computer”somefile.txt
would display all of the lines including "computer". I am eager to learn and if anyone has alternative ways I would like to hear!
将显示包括“计算机”在内的所有行。我渴望学习，如果有人有其他方式我想听！
Thx everyone
大家好
3 个解决方案
#1
17
Use the match count option of grep
使用grep的匹配计数选项
grep -m 1 "computer" somefile.txt
Note that grep is non standard across un*x's so while http://www.gnu.org/software/grep/ supports this, if your distro or unix does not this will not work.
请注意，grep在un * x中是非标准的，所以虽然http://www.gnu.org/software/grep/支持这一点，但如果你的发行版或unix不支持，那么这将不起作用。
#2
10
Pipes are your friend:
管道是你的朋友：
grep "computer" somefile.txt | head -n1
#3
-1
Is this homework?
这是家庭作业吗？
grep -v "computer" somefile.txt | head -n 1
Comes to mind the quickest.
想到最快的。
#1
17
Use the match count option of grep
使用grep的匹配计数选项
grep -m 1 "computer" somefile.txt
Note that grep is non standard across un*x's so while http://www.gnu.org/software/grep/ supports this, if your distro or unix does not this will not work.
请注意，grep在un * x中是非标准的，所以虽然http://www.gnu.org/software/grep/支持这一点，但如果你的发行版或unix不支持，那么这将不起作用。
#2
10
Pipes are your friend:
管道是你的朋友：
grep "computer" somefile.txt | head -n1
#3
-1
Is this homework?
这是家庭作业吗？
grep -v "computer" somefile.txt | head -n 1
Comes to mind the quickest.
想到最快的。