Python：如何在两个列表中对元素进行乘法和求和（不使用库）？

I've two lists (m1 and m2) containing lists of numbers. I'm trying to do element-wise multiplication and sum including the cross product to obtaining a final list (result) as follow:

我有两个包含数字列表的列表（m1和m2）。我正在尝试进行元素乘法和求和，包括交叉乘积以获得最终列表（结果），如下所示：

m1 = [[1, 2, 3], [4, 5, 6]]
m2 = [[7, 9, 2], [8, 1, 3]]

[[1*7+2*9+3*2,1*8+2*1+3*3],[4*7+5*9+6*2,4*8+5*1+6*3]]

result = [[31,19],[85,55]]

3 个解决方案

#1

You can play with python built-in functions and a nested list comprehension :

您可以使用python内置函数和嵌套列表解析：

>>> [[sum(t*k for t,k in zip(i,j)) for j in m2] for i in m1]
[[31, 19], [85, 55]]

You can also use itertools.product to find the products between sub-lists :

您还可以使用itertools.product查找子列表之间的产品：

>>> from itertools import product
>>> [sum(t*k for t,k in zip(i,j)) for i,j in product(m1,m2)]
[31, 19, 85, 55]

#2

Let's break the problem into the smaller pieces. At the lowest level, we have two small lists: [1, 2, 3] and [7, 9, 2] and want to multiply them, item by item:

让我们把问题分解成更小的部分。在最低级别，我们有两个小列表：[1,2,3]和[7,9,2]，并希望逐项相乘：

item1 = [1, 2, 3]
item2 = [7, 9, 2]
zip(item1, item2)                        # ==> [(1, 7), (2, 9), (3, 2)]
[x * y for x, y in zip(item1, item2)]    # ==> [7, 18, 6]
sum(x * y for x, y in zip(item1, item2)) # ==> 31

Now, we can put this to work inside a double loop:

现在，我们可以在双循环中使用它：

[[sum(x * y for x, y in zip(item1, item2)) for item2 in m2] for item1 in m1]
# ==> [[31, 19], [85, 55]]

#3

If you want it without importing any modules, you can do it this way:

如果你想要它而不导入任何模块，你可以这样做：

>>> m1 = [[1, 2, 3], [4, 5, 6]]
>>> m2 = [[7, 9, 2], [8, 1, 3]]
>>> [[sum(map(lambda (s,t):s*t, zip(x,y))) for y in m2] for x in m1]
[[31, 19], [85, 55]]

#1