如何使用正则表达式拆分字符串以返回值列表？

How can I take the string foo[]=1&foo[]=5&foo[]=2 and return a collection with the values 1,5,2 in that order. I am looking for an answer using regex in C#. Thanks

如何取字符串foo [] = 1&foo [] = 5&foo [] = 2并按顺序返回值为1,5,2的集合。我在C#中使用正则表达式寻找答案。谢谢

8 个解决方案

#1

In C# you can use capturing groups

在C#中,您可以使用捕获组

    private void RegexTest()
    {
        String input = "foo[]=1&foo[]=5&foo[]=2";
        String pattern = @"foo\[\]=(\d+)";

        Regex regex = new Regex(pattern);

        foreach (Match match in regex.Matches(input))
        {
            Console.Out.WriteLine(match.Groups[1]);
        }
    }

#2

I don't know C#, but...

我不知道C#,但......

In java:

String[] nums = String.split(yourString, "&?foo[]");

The second argument in the String.split() method is a regex telling the method where to split the String.

String.split()方法中的第二个参数是一个正则表达式,告诉方法在哪里拆分String。

#3

I'd use this particular pattern:

我会用这个特殊的模式:

string re = @"foo\[\]=(?<value>\d+)";

So something like (not tested):

所以像(未经测试):

Regex reValues = new Regex(re,RegexOptions.Compiled);
List<integer> values = new List<integer>();

foreach (Match m in reValues.Matches(...putInputStringHere...)
{
   values.Add((int) m.Groups("value").Value);
}

#4

Use the Regex.Split() method with an appropriate regex. This will split on parts of the string that match the regular expression and return the results as a string[].

使用Regex.Split()方法和适当的正则表达式。这将拆分与正则表达式匹配的字符串部分,并将结果作为字符串[]返回。

Assuming you want all the values in your querystring without checking if they're numeric, (and without just matching on names like foo[]) you could use this: "&?[^&=]+="

假设您想要查询字符串中的所有值而不检查它们是否为数字(并且不仅仅匹配foo []等名称),您可以使用:“&?[^&=] + =”

string[] values = Regex.Split(“foo[]=1&foo[]=5&foo[]=2”, "&?[^&=]+=");

Incidentally, if you're playing with regular expressions the site http://gskinner.com/RegExr/ is fantastic (I'm just a fan).

顺便说一句,如果你正在使用正则表达式,网站http://gskinner.com/RegExr/太棒了(我只是一个粉丝)。

#5

Assuming you're dealing with numbers this pattern should match:

假设你正在处理数字,这个模式应该匹配:

/=(\d+)&?/

#6

This should do:

这应该做:

using System.Text.RegularExpressions;

Regex.Replace(s, !@"^[0-9]*$”, "");

Where s is your String where you want the numbers to be extracted.

其中s是您想要提取数字的String。

#7

Just make sure to escape the ampersand like so:

只要确保像这样逃避&符号:

/=(\d+)\&/

#8

Here's an alternative solution using the built-in string.Split function:

这是使用内置string.Split函数的替代解决方案:

string x = "foo[]=1&foo[]=5&foo[]=2";
string[] separator = new string[2] { "foo[]=", "&" };
string[] vals = x.Split(separator, StringSplitOptions.RemoveEmptyEntries);

#1