【LeetCode】622. Design Circular Queue 解题报告(Python & C++)

时间:2024-04-29 00:12:42

作者: 负雪明烛
id: fuxuemingzhu
个人博客: http://fuxuemingzhu.cn/


题目地址:https://leetcode.com/problems/design-circular-queue/description/

题目描述

Design your implementation of the circular queue. The circular queue is a linear data structure in which the operations are performed based on FIFO (First In First Out) principle and the last position is connected back to the first position to make a circle. It is also called ‘Ring Buffer’.
One of the Benefits of the circular queue is that we can make use of the spaces in front of the queue. In a normal queue, once the queue becomes full, we can not insert the next element even if there is a space in front of the queue. But using the circular queue, we can use the space to store new values.
Your implementation should support following operations:

  • MyCircularQueue(k): Constructor, set the size of the queue to be k.
  • Front: Get the front item from the queue. If the queue is empty, return -1.
  • Rear: Get the last item from the queue. If the queue is empty, return -1.
  • enQueue(value): Insert an element into the circular queue. Return true if the operation is successful.
  • deQueue(): Delete an element from the circular queue. Return true if the operation is successful.
  • isEmpty(): Checks whether the circular queue is empty or not.
  • isFull(): Checks whether the circular queue is full or not.

Example:

MyCircularQueue circularQueue = new MycircularQueue(3); // set the size to be 3

circularQueue.enQueue(1);  // return true

circularQueue.enQueue(2);  // return true

circularQueue.enQueue(3);  // return true

circularQueue.enQueue(4);  // return false, the queue is full

circularQueue.Rear();  // return 3

circularQueue.isFull();  // return true

circularQueue.deQueue();  // return true

circularQueue.enQueue(4);  // return true

circularQueue.Rear();  // return 4

Note:

  • All values will be in the range of [1, 1000].
  • The number of operations will be in the range of [1, 1000].
  • Please do not use the built-in Queue library.

题目大意

实现一个环形链表。

解题方法

用直的代替弯的

环形的肯定不好设计,于是我就是直接弄了一个直的,不断的整体往后移,保持最大容纳k个元素。只需要维护好front和rear指针,就能模拟出来一个环状队列。

需要注意的几个点:

  1. Front()和Rear()函数要判断是否为空;
  2. 在得到元素的时候rear-1,而front不用。

代码如下:

class MyCircularQueue(object):

    def __init__(self, k):
"""
Initialize your data structure here. Set the size of the queue to be k.
:type k: int
"""
self.queue = []
self.size = k
self.front = 0
self.rear = 0 def enQueue(self, value):
"""
Insert an element into the circular queue. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if self.rear - self.front < self.size:
self.queue.append(value)
self.rear += 1
return True
else:
return False def deQueue(self):
"""
Delete an element from the circular queue. Return true if the operation is successful.
:rtype: bool
"""
if self.rear - self.front > 0:
self.front += 1
return True
else:
return False def Front(self):
"""
Get the front item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[self.front] def Rear(self):
"""
Get the last item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[self.rear - 1] def isEmpty(self):
"""
Checks whether the circular queue is empty or not.
:rtype: bool
"""
return self.front == self.rear def isFull(self):
"""
Checks whether the circular queue is full or not.
:rtype: bool
"""
return self.rear - self.front == self.size # Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()

在经过做641. Design Circular Deque之后,我发现其实头尾指针都是不重要的,只要我们维护好这个list,使得这个list中保存的就是队列里面应该剩下来的元素即可。

所以删除头指针front的代码如下:

class MyCircularQueue(object):

    def __init__(self, k):
"""
Initialize your data structure here. Set the size of the queue to be k.
:type k: int
"""
self.queue = []
self.size = k
self.rear = 0 def enQueue(self, value):
"""
Insert an element into the circular queue. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if not self.isFull():
self.queue.append(value)
self.rear += 1
return True
else:
return False def deQueue(self):
"""
Delete an element from the circular queue. Return true if the operation is successful.
:rtype: bool
"""
if not self.isEmpty():
self.queue.pop(0)
self.rear -= 1
return True
else:
return False def Front(self):
"""
Get the front item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[0] def Rear(self):
"""
Get the last item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[self.rear - 1] def isEmpty(self):
"""
Checks whether the circular queue is empty or not.
:rtype: bool
"""
return 0 == self.rear def isFull(self):
"""
Checks whether the circular queue is full or not.
:rtype: bool
"""
return self.rear == self.size # Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()

同理,只要维护的list中保存的元素和队列应该有的元素相同的,那么末尾指针rear一直指向了list的结尾,所以,可以把rear也删除。

删除front和rear的代码如下:

class MyCircularQueue(object):

    def __init__(self, k):
"""
Initialize your data structure here. Set the size of the queue to be k.
:type k: int
"""
self.queue = []
self.size = k def enQueue(self, value):
"""
Insert an element into the circular queue. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if not self.isFull():
self.queue.append(value)
return True
else:
return False def deQueue(self):
"""
Delete an element from the circular queue. Return true if the operation is successful.
:rtype: bool
"""
if not self.isEmpty():
self.queue.pop(0)
return True
else:
return False def Front(self):
"""
Get the front item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[0] def Rear(self):
"""
Get the last item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[-1] def isEmpty(self):
"""
Checks whether the circular queue is empty or not.
:rtype: bool
"""
return 0 == len(self.queue) def isFull(self):
"""
Checks whether the circular queue is full or not.
:rtype: bool
"""
return len(self.queue) == self.size # Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()

数组循环利用

环形队列的物理结构就是一个固定长度的数组,然后前后指针到达尾部之后,移到最前。使用了first指针指向队列的首部,使用了last指针指向了队列的尾部的后一个元素。

C++代码如下:

class MyCircularQueue {
public:
/** Initialize your data structure here. Set the size of the queue to be k. */
MyCircularQueue(int k) {
q = vector<int>(k + 1, 0);
K = k;
first = 0;
last = 0;
count = 0;
} /** Insert an element into the circular queue. Return true if the operation is successful. */
bool enQueue(int value) {
if (!isFull()) {
q[last] = value;
last = (last + 1 + K) % K;
count ++;
return true;
} else {
return false;
}
} /** Delete an element from the circular queue. Return true if the operation is successful. */
bool deQueue() {
if (!isEmpty()) {
int val = q[first];
first = (first + 1 + K) % K;
count --;
return true;
} else {
return false;
}
} /** Get the front item from the queue. */
int Front() {
if (isEmpty())
return -1;
return q[first];
} /** Get the last item from the queue. */
int Rear() {
if (isEmpty())
return -1;
return q[(last - 1 + K) % K];
} /** Checks whether the circular queue is empty or not. */
bool isEmpty() {
return count == 0;
} /** Checks whether the circular queue is full or not. */
bool isFull() {
return count == K;
}
private:
vector<int> q;
int first;
int last;
int K;
int count;
}; /**
* Your MyCircularQueue object will be instantiated and called as such:
* MyCircularQueue* obj = new MyCircularQueue(k);
* bool param_1 = obj->enQueue(value);
* bool param_2 = obj->deQueue();
* int param_3 = obj->Front();
* int param_4 = obj->Rear();
* bool param_5 = obj->isEmpty();
* bool param_6 = obj->isFull();
*/

日期

2018 年 7 月 13 日 —— 早起困一上午,中午必须好好休息才行啊
2018 年 12 月 12 日 —— 双十二